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anonymous

  • one year ago

What is the rate of change for f(x) = –2 cos 4x – 3 on the interval from x = 0 to x = pi/4

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  1. anonymous
    • one year ago
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    Answer choices A. 2/pi B.pi/2 C.16/pi D. pi/16

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    okay so plug in values for both 0 and π/4

  4. anonymous
    • one year ago
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    and then use (f(0)-f(π/4))/(0-4)

  5. anonymous
    • one year ago
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    don't forget to medal... any questions just message me

  6. anonymous
    • one year ago
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    Hey sorry my computer had to be restarted. How do I give you a medal?

  7. anonymous
    • one year ago
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    you just click best answer, and it medals

  8. anonymous
    • one year ago
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    @cramos725 could you help me a bit more?

  9. anonymous
    • one year ago
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    sure

  10. anonymous
    • one year ago
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    what do u need help on?

  11. anonymous
    • one year ago
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    I am new to this type of problem entirely so could you show me the plugging in part?

  12. anonymous
    • one year ago
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    okay sure... so f(x) = –2 cos 4x – 3 when you plug in 0, you have -2 cos(4(0)) -3 which is equal to -2 cos(0) -3 = -2(1)-3 =-2-3 =-5

  13. anonymous
    • one year ago
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    oh ok I see what I did wrong

  14. anonymous
    • one year ago
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    when you plug in π/4, you get -2(cos4(π/4))-3 so you get -2 cos(π) -3 =-2(-1)-3 =-1

  15. anonymous
    • one year ago
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    glad i could help

  16. anonymous
    • one year ago
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    and the denominator should be (0-π/4)

  17. anonymous
    • one year ago
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    i made a mistake typing it in earlier

  18. anonymous
    • one year ago
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    you get -5-(-1) which is -4 all over 0-π/4 -4/(-π/4) which is 16/π

  19. anonymous
    • one year ago
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    oh i see. Thank you so much I really appreciate yout time.

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