A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Simplify: (sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2
anonymous
 one year ago
Simplify: (sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2 (sin^2cos^2) + (sin^2+cos^2) (y^2x^2) + (y^2+x^2) eliminate x^2 (y^2+y^2)= 2sin^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please check my answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 @KyanTheDoodle @mathmath333 @sleepyjess

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (x+y)^2 \cancel= x^2 + y^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nope let sin = x cos = y so \[(x y)^2=(xy)(xy)\] now foil

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My options: A. −sin2 Θ B. −cos2 Θ C. 0 D. 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright so u didn't foil it right \[(xy)^2 \cancel= x^2 y^2\] (xy)^2 is same as (xy)(xy ) can you foil these ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one moment so i can foil

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Open the square Then put sin^2x+cos^x=1 You get 12sinxcosx +1+2sinxcosx =1+1=2 (I'm putting theta as x)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right (x+y) = x^2 +2xy +y^2 :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(xy)^2 is what i solved for

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1expand you have to foil it (Xy)^2 is same as (xy)(xy)

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0No 2xy is replaced by2xy

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm x^2 2xy +y^2 + x^2 +2xy +y^2\]\] combine like terms

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0I hope you can add the two square carefully.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep now replace x and y by sin and cos \[\huge\rm 2 \sin^2 + 2\cos^2\] take out common factor apply this identity \[\large\rm sin^2 \theta + \cos^2 \theta = 1 \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \color{reD}{ 2} \sin^2 +\color{reD}{ 2}\cos^2\] \[\huge\rm \color{reD}{ 2} (\sin^2 \theta +cos^2 \theta)\] \[\huge\rm \color{reD}{ 2} (1) =2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much for your help @Nnesha i really appreciate it.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.