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anonymous
 one year ago
CANT DROP THIS COARSE PLEASE HELP ASAP!ONLY REAL HELP NO FAKE BS! sandbag was thrown downward from a building. The function f(t) = 16t2  32t + 128 shows the height f(t), in feet, of the sandbag after t seconds.
Factor the function f(t) and use the factors to interpret the meaning of the xintercept of the function.
Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph?
Use your answer in part B to determine the axis of symmetry for f(x)?
HOMEWORK HELP ME PLEASE!!!!!!!!!!!!
anonymous
 one year ago
CANT DROP THIS COARSE PLEASE HELP ASAP!ONLY REAL HELP NO FAKE BS! sandbag was thrown downward from a building. The function f(t) = 16t2  32t + 128 shows the height f(t), in feet, of the sandbag after t seconds. Factor the function f(t) and use the factors to interpret the meaning of the xintercept of the function. Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? Use your answer in part B to determine the axis of symmetry for f(x)? HOMEWORK HELP ME PLEASE!!!!!!!!!!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a test question. Like I said before, we don't help on tests.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like I said stay off of my page unless you are actually gonna help me! @Aureyliant leave me alone

acxbox22
 one year ago
Best ResponseYou've already chosen the best response.1do you need any physical or mental assistance in answering this question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hi @acxbox22 can you help me please? and actually both lol I cant focus long enough to figure out the answer and I honestly don't even know where to start.

acxbox22
 one year ago
Best ResponseYou've already chosen the best response.1you already asked this q b4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nobody helped me before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Aureyliant @MeowLover17 do you know how many people ask this same question and you aren't spying on them... get off of my page and let me get help stop stalking me and leave me the hell alone! why you chose me to be assertive too I don't know but you aren't my parents go ahead and report me keep on helping others I don't really care just leave me alone im done with this game you are playing. go away and leave me alone.

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.1You got a lot of flack on this question. For good reason. Anyway, the question asks to factor. So let's do that. \[16t^232t+128\] Let's factor a 16 out of everything. \[16(t^2+2t8) \] Note that this can be factored more. \[16(t+4)(t2)\] Do you understand what I've done so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes I undertand so far...

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.1Ouch. This question should be closed. Don't insult the ones who try to help.

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1i took this same test do you want the answers?

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1I have a LARGE explanation with each :)

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1Here ill post the link look if you want otherwise your loss :D Enjoy! http://pages.citebite.com/a4o3b6r4a2tjy

MeowLover17
 one year ago
Best ResponseYou've already chosen the best response.0^ All the answers are up there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thing is @sh3lsh they aren't helping they are insulting me and my capabilities and then following me around they aren't here to help trust me...and @Aureyliant it depends who is jumping:)

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1Hope you found your answers :D If you need more dont hesitate ask me!
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