three cards are drawn from an ordinary deck of 52 cards. each card is replaced in the deck before the next card is drawn. what is the probability that at least one of the cards was a spade

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- anonymous

- schrodinger

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- anonymous

Ok first how many spades are in a deck of cards

- anonymous

13

- anonymous

52C3

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- anonymous

soo divde 52 cards by 13 cards

- anonymous

what do i put in the numerator?

- anonymous

it says at least 1 spade so im confused

- anonymous

round it to the nearest whole number

- anonymous

P = 1 - P(no spade cards)

- anonymous

im so confused now lol

- anonymous

at least 1 spade card means P(1 spade) + P(2 spades) + P(3 spades). If you do this way, you'd have to calculate 3 times. But instead, just calculate the complement and subtract from 1

- anonymous

wont i get a negative number if i subtract from 1?

- anonymous

No, you won't

- anonymous

what

- anonymous

what would you get if you do P(no spade cards) ?

- anonymous

39/52

- anonymous

oh i have to subtract the fraction

- anonymous

1-(39/52)=1/4

- anonymous

you are drawing 3 cards, not 1 card

- anonymous

1 - (39/52)^3

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