anonymous
  • anonymous
three cards are drawn from an ordinary deck of 52 cards. each card is replaced in the deck before the next card is drawn. what is the probability that at least one of the cards was a spade
Mathematics
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anonymous
  • anonymous
three cards are drawn from an ordinary deck of 52 cards. each card is replaced in the deck before the next card is drawn. what is the probability that at least one of the cards was a spade
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Ok first how many spades are in a deck of cards
anonymous
  • anonymous
13
anonymous
  • anonymous
52C3

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anonymous
  • anonymous
soo divde 52 cards by 13 cards
anonymous
  • anonymous
what do i put in the numerator?
anonymous
  • anonymous
it says at least 1 spade so im confused
anonymous
  • anonymous
round it to the nearest whole number
anonymous
  • anonymous
P = 1 - P(no spade cards)
anonymous
  • anonymous
im so confused now lol
anonymous
  • anonymous
at least 1 spade card means P(1 spade) + P(2 spades) + P(3 spades). If you do this way, you'd have to calculate 3 times. But instead, just calculate the complement and subtract from 1
anonymous
  • anonymous
wont i get a negative number if i subtract from 1?
anonymous
  • anonymous
No, you won't
anonymous
  • anonymous
what
anonymous
  • anonymous
what would you get if you do P(no spade cards) ?
anonymous
  • anonymous
39/52
anonymous
  • anonymous
oh i have to subtract the fraction
anonymous
  • anonymous
1-(39/52)=1/4
anonymous
  • anonymous
you are drawing 3 cards, not 1 card
anonymous
  • anonymous
1 - (39/52)^3

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