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anonymous
 one year ago
Can anyone explain how to prove(sin x)(tan x cos x  cot x cos x) = 1  2 cos2x
This proving trig functions has got me confused
anonymous
 one year ago
Can anyone explain how to prove(sin x)(tan x cos x  cot x cos x) = 1  2 cos2x This proving trig functions has got me confused

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0write tan in terms of sin over cos \[\huge\rm tan \theta = \frac{ \sin }{ \cos }\] change that and remember cot is reciprocal of tan

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm sinx (\color{reD}{tanx} cosx  \color{red}{cotx} cosx)\]\[\large\rm sinx(\color{Red}{\frac{ \sin x}{ cosx }} cosx  \cot x cosx)\] cot x = what ?

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Sinx(sinx/cosx×coscosx/sinx×cosx) =sin^2xcos^2x. (Multiply sin inside the bracket) =cos2x

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0The answer is incorrect

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @lala102 Give me a sec \(\color{blue}{\text{End of Quote}}\) okay :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay i am so confused gahhhh!!! I really hate trig. Do I distribute? I do not know what I am doing, but I'm trying. Math is just my enemy

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0cot x = what ? if tan = sin/cos

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Want to solve it then love it play with it . It's not your enemy.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay I got you now cotx is 1/tanx right

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0nope tan and cot are reciprocal of each other so if tan = sin /cos then cot = cos /sin

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm sinx(\color{Red}{\frac{ \sin x}{ cosx }} cosx  \frac{cosx}{sin} cosx)\] now solve the parentheses first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Um okay.... Man I must be looking at the wrong set of notes. I'm sorry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0both sides are equal you can verify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry I'm going slow its somethinwrong with my phone

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0alright let sin x = a and cos x = b \[\large\rm a(\color{Red}{\frac{ a}{ b }}( b) \frac{b}{a} (b))\] simple algebra can you solve it now
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