anonymous
  • anonymous
Can anyone explain how to prove(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x This proving trig functions has got me confused
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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Nnesha
  • Nnesha
write tan in terms of sin over cos \[\huge\rm tan \theta = \frac{ \sin }{ \cos }\] change that and remember cot is reciprocal of tan
Nnesha
  • Nnesha
\[\large\rm sinx (\color{reD}{tanx} cosx - \color{red}{cotx} cosx)\]\[\large\rm sinx(\color{Red}{\frac{ \sin x}{ cosx }} cosx - \cot x cosx)\] cot x = what ?
anonymous
  • anonymous
Give me a sec

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Pawanyadav
  • Pawanyadav
Sinx(sinx/cosx×cos-cosx/sinx×cosx) =sin^2x-cos^2x. (Multiply sin inside the bracket) =-cos2x
Pawanyadav
  • Pawanyadav
The answer is incorrect
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @lala102 Give me a sec \(\color{blue}{\text{End of Quote}}\) okay :-)
anonymous
  • anonymous
Okay i am so confused gahhhh!!! I really hate trig. Do I distribute? I do not know what I am doing, but I'm trying. Math is just my enemy
Nnesha
  • Nnesha
where is your work ??
Nnesha
  • Nnesha
cot x = what ? if tan = sin/cos
Pawanyadav
  • Pawanyadav
Want to solve it then love it play with it . It's not your enemy.
anonymous
  • anonymous
Oh okay I got you now cotx is 1/tanx right
Nnesha
  • Nnesha
nope tan and cot are reciprocal of each other so if tan = sin /cos then cot = cos /sin
Nnesha
  • Nnesha
\[\large\rm sinx(\color{Red}{\frac{ \sin x}{ cosx }} cosx - \frac{cosx}{sin} cosx)\] now solve the parentheses first
anonymous
  • anonymous
Um okay.... Man I must be looking at the wrong set of notes. I'm sorry
Nnesha
  • Nnesha
what do yo mean ??
Nnesha
  • Nnesha
both sides are equal you can verify
anonymous
  • anonymous
I'm sorry I'm going slow its somethinwrong with my phone
Nnesha
  • Nnesha
alright let sin x = a and cos x = b \[\large\rm a(\color{Red}{\frac{ a}{ b }}( b)- \frac{b}{a} (b))\] simple algebra can you solve it now
anonymous
  • anonymous
Yes thank you!
Nnesha
  • Nnesha
got it ?

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