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anonymous
 one year ago
Find a quadratic function f(x)=ax^2+bx+c for the parabola with minimum value 5 and xintercepts 3 and 7??
anonymous
 one year ago
Find a quadratic function f(x)=ax^2+bx+c for the parabola with minimum value 5 and xintercepts 3 and 7??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have to input the minimum value and the x,y coordinates into the vertex form of a parabola. Then convert the vertex form to standard form .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you so much! @sophiav95

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0a really easy solution is to recognize the line of symmetry is halfway between the intercepts... and the vertex lies on the line of symmetry (3 + 7)/2 = 2 so the line of symmetry is x = 2 you know the min value y = 5 so the vertex is (2, 5) so then substitute the point into the vertex from of the parabola \[y = (x  h)^2 + k\] where (h, k) is the vertex
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