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anonymous
 one year ago
Help for a medal?
anonymous
 one year ago
Help for a medal?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Identify the factors of x2  4x  21.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well can you think of 2 numbers, one positive and one negative, that will add to 4 and multiply to 21?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And yeah, that is x^24x21

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can't think of one besides 5 and 9. But when multiplied that will equal 45 so thats not it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't focus on the "add to 4" part first. Think of the "multiply to 21" first. What pairs of numbers can you multiply to get 21?

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0x^27x+3x21 x(x7)+3(x7) (x+3)(x7) are the factors

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks Pawanyadav but I want to learn how to do this too.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, would it be 7 and 3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, it'd be 7 and 3. Once you know that, all you have to do is put it together \[\large (x7)(x+3)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, okay. Seems pretty simple. Will these kind of questions always be like this? Like, do I always have to find what you multiply and add to get that certain number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And @Pawanyadav I'll give you a fan since you weren't incorrect, and Sadist a medal since he walked me through it.

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Break 4 in such a way so that the two break parts has the product 21 and definitely the parts are broken from 4 they will give their sum equal to4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well it'll definitely get harder once they get more complicated. I like this method as a beginning method though, since it give a good understanding of how to do it and you can always fall back to it.

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Do you understand now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, I understand now. Thanks you two.
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