A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Trig / Pre Cal/ identities Am I on the right path?
Please guide me and do not give me the answers
\[ (\tan x + \sin x)(1cos x) = \sin^2 x \tan x \]
Do I multiply like with foil starting with tan or do I turn tan into \( \frac{sin x}{cox x} \)
and then use foil?
anonymous
 one year ago
Trig / Pre Cal/ identities Am I on the right path? Please guide me and do not give me the answers \[ (\tan x + \sin x)(1cos x) = \sin^2 x \tan x \] Do I multiply like with foil starting with tan or do I turn tan into \( \frac{sin x}{cox x} \) and then use foil?

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1foil! :) i guess that will be great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just with tan \[ \tan x (\tan x)(\cos x) + \sin x (\sin x)(\cos x) \] correct so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, how do I approch it from here? do I turn all the tan into sin / cos? and work it out? \[ \tan x (\tan x)(\cos x) + \sin x (\sin x)(\cos x) \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes convert 2nd tan to sin /cos and let me find notebook and a pencil :3 hehe

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1make sure question is right :3 :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1is it equal to tanxsinx or tan^2xsinx ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have \[ \tan x \sin x + \sin x (\sin x)(\cos x) = \sin^2 x \tan x \] \[ \tan x (\sin x)(\cos x) = \sin^2 x \tan x \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yeah so for the final answer i got sinx tanx so that's why ..hm are u sure it's sin square ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1next step is to change tan to sin/cos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it is sin^2 x tan x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \tan x (\sin x)(\cos x) = \sin^2 x \tan x \) \( \frac{sin x}{cos x} (\sin x)(\cos x) = \sin^2 x \tan x \) ????

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\( \huge\rm \frac{sin x}{cos x} (\sin x)(\cos x) = \) ???? find common denominator :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am using cos as the common denominator. that is correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I got \[ \frac{sin x}{cos x} (\sin x)(\cos x) = \sin^2 x \tan x \] \[ \frac{(sin x)(cos x)}{\cos x} \frac{((\sin x))}{\cos x} \frac{\cos^2}{cos} = \sin^2 x \tan x \] correct???

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[ \frac{(sin x)(\cancel{cos x})}{\cos x} \frac{((\sin x))}{\cos x} \frac{\cos^2}{cos} = \sin^2 x \tan x \] multiply cosx/1 so when you multiply first fraction by cos both cos will cancel each other out

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so there isn't supposed to be any cosx \[ \frac{(sin x)}{\cos x} \frac{((\sin x cos^2x))}{cos x} = \sin^2 x \tan x \] like this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh right!!! Made a boo boo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One sec, now we should have

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ \frac{(sin x)}{\cos x} \frac{((\sin x cos^2x))}{cos x} = \sin^2 x \tan x \] \[ \frac{(sin x)}{\cos x} \frac{((\sin x (1\sin^2 x)2x))}{cos x} = \sin^2 x \tan x \] Ok I am lost

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ \frac{(sin x)}{\cos x} \frac{((\sin x (1cos^2 x))}{cos x} = \sin^2 x \tan x \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\cos x \times \frac{ \sin x }{ \cos x}  \frac{ sinx \cos x }{ \cos } \times \cos \] multiply dw:1434231940649:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\cos x \times \frac{ \sin x }{ \cos x}  \frac{ sinx \cos x }{ \cos } \times \cos \] \[\huge\rm \frac{ \sin x  sinx cosx (cosx) }{ cosx }\]you will get this let me if that doesn't make sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that makes sence

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright now multiply cos x times cos x = ?? \[\huge\rm \frac{ \sin x  sinx \color{Red}{cosx (cosx)} }{ cosx }\]you will get this let me if that doesn't make sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Was this originally \[\frac{ \sin x }{ \cos x}  \frac{ \sin x \cos^2 x }{ \cos x } \] \[\cos x \times \frac{ \sin x }{ \cos x}  \frac{ \sin x \cos^2 x }{ 1 } \times \cos \] \[\cos x \times \frac{ \sin x }{ \cos x}  \frac{ \sin x \cos x }{ 1 } \times \cos \] Is that what we did there?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1we know that common denominator is cos so we multiplied numerator by cos x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1if the original fraction already have a same denominator as common denominator so u just have to carrry it downdw:1434232700973:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If we did that we have \[ \cos \times \frac{ \sin x }{ \cos x}  \frac{ \sin x \cos^2 x }{ \cos x } \times \cos \] \[ \sin x  (\sin x)(\cos^2 x) \] ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1first of all we know that cosx is common denominator so that should be at the denominator \[\frac{ ?????? }{ \cos x }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1after that we have to multiply both fraction by cos If we did that we have \[ \cos \times \frac{ \sin x }{ \cos x}  \frac{ \sin x \cos^2 x }{ \cos x } \times \cos \] \[\large\rm \frac{?????????}{cosx }\] ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1wait a sec that's not cos^2 yet

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Nixy If we did that we have \[ \cos \times \frac{ \sin x }{ \cos x}  \frac{ \sin x \cos^2 x }{ \cos x } \times \cos \] \[ \sin x  (\sin x)(\cos^2 x) \] ?? \(\color{blue}{\text{End of Quote}}\) we know common denominator is cosx now we have to find numerator \[\frac{ ?????? }{ \cos x }\] original equation is \[\huge\rm \frac{ sinx }{ cosx }  \frac{ sinx \cos x }{ 1 }\] to find out numerator we should multiply both fraction by cosx(which is common denominator ) \[\large\rm cosx \times \frac{ sinx }{ cosx }  \frac{ sinx \cos x }{ 1 } \times cosx\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1and that's how \[\large\rm \cancel{cosx} \times \frac{ sinx }{\cancel{ cosx} }  \frac{ sinx \cos^2 x }{ 1 } \] that's the numerator part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, I think we are on the same page now WOW this stuff gets confusing lol Ok I am where you are at

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1do you got that denominator thingy ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we have \[ \large\rm\frac{ sinx }{{ 1} }  \frac{ sinx \cos^2 x }{ 1 } \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1that's the numerator what's our common denominator ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From what section?? I am going from here \[ \large\rm \cancel{cosx} \times \frac{ sinx }{\cancel{ cosx} }  \frac{ sinx \cos^2 x }{ 1 } \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1sinx/1 = sinx so you can write it as \[\huge\rm \frac{ sinx  sinxcos^2x }{ cosx }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Nnesha sinx/1 = sinx so you can write it as \[\huge\rm \frac{ sinx  sinxcos^2x }{ cosx }\] \(\color{blue}{\text{End of Quote}}\) do you understand this step ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I understand Next ? \[ \huge\rm \frac{ sinx  sinx(1sin^2) }{ cosx } \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nope next step is to take out common term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[ \huge\rm \frac{\color{ReD}{ sinx} \color{ReD}{ sinx}cos^2x}{ cosx } \] factor the numerator :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1let sinx = a cosx = b so you can write it as \[\large\rm (aab^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So this \( (aab^2) = (ab^2a) = (ab+a)(aba) \) correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I cannot believe this one problem is like this. It has been an hour and 30 minutes lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nope what is common in these both terms a  ab^2 ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right!!! so now change it back to sin cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[ \huge\rm \frac{\color{ReD}{ sinx}( 1cos^2x)}{ cosx } \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and that is the answer :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1separate it \[ \huge\rm \frac{\color{ReD}{ sinx} }{ cosx } \times (1cos^2x) \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0WOW, I cannot believe we got a problem like this. Some of these things take a long time.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1practice more and more! then you will be able to finish it just in 5 minutes :3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You work them one way then come to find out it is wrong then work them another and repeat and finally you get it lol This was the worst one yet!!! thank you for your help!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I do not have time to practice we have a week to fit a lot in and then we move on. Next week we probably will not even mess with these. idk

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1ohh but still try do 2 question every night :3 = nightmares haha jk
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.