anonymous
  • anonymous
What is the equation of the line that passes through (4, -1) and (-2, 3)? a) 2x-3y-5=0 b) 2x+3y-5=0 c) -2x+3y-5=0
Mathematics
jamiebookeater
  • jamiebookeater
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pooja195
  • pooja195
We need to find the slope first so we need to use the slope formula \[\huge~\rm~\frac{ y_2-y_1 }{ x_2-x_1 }\]
Pawanyadav
  • Pawanyadav
y-y1={y2-y1} /(x2-x1) ×(x-x1)
anonymous
  • anonymous
I got 1/3 for the slope formula, is that right?? @pooja195

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pooja195
  • pooja195
i was thinking 1 .. ...
pooja195
  • pooja195
3-1=2 -2+4=2 2/2=1
Pawanyadav
  • Pawanyadav
Put y2=3 Y1=-1 x2=-2 x1=4
pooja195
  • pooja195
???
anonymous
  • anonymous
i did the formula wrong... i got it now
pooja195
  • pooja195
no
pooja195
  • pooja195
my bad 3+1=4 -2+4=2 4/2=2 :/
anonymous
  • anonymous
So we are going to use the slope formula first so \[\large \frac{-1+(-3)}{4-(-2)}\]

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