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anonymous

  • one year ago

What is the equation of the line that passes through (4, -1) and (-2, 3)? a) 2x-3y-5=0 b) 2x+3y-5=0 c) -2x+3y-5=0

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  1. pooja195
    • one year ago
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    We need to find the slope first so we need to use the slope formula \[\huge~\rm~\frac{ y_2-y_1 }{ x_2-x_1 }\]

  2. Pawanyadav
    • one year ago
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    y-y1={y2-y1} /(x2-x1) ×(x-x1)

  3. anonymous
    • one year ago
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    I got 1/3 for the slope formula, is that right?? @pooja195

  4. pooja195
    • one year ago
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    i was thinking 1 .. ...

  5. pooja195
    • one year ago
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    3-1=2 -2+4=2 2/2=1

  6. Pawanyadav
    • one year ago
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    Put y2=3 Y1=-1 x2=-2 x1=4

  7. pooja195
    • one year ago
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    ???

  8. anonymous
    • one year ago
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    i did the formula wrong... i got it now

  9. pooja195
    • one year ago
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    no

  10. pooja195
    • one year ago
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    my bad 3+1=4 -2+4=2 4/2=2 :/

  11. anonymous
    • one year ago
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    So we are going to use the slope formula first so \[\large \frac{-1+(-3)}{4-(-2)}\]

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