solve for x:
log(5)(11-6x) = log(5)(1-x)

solve for x:
log(5)(11-6x) = log(5)(1-x)

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hint: \[\huge\rm log_b x = \log_b y\]
\[\huge\rm\cancel { log_b} x = \cancel{\log_b} y\]
x=y

Ohhh... X = 2 right?

Or is it no solution?

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