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anonymous
 one year ago
Help for a medal?
anonymous
 one year ago
Help for a medal?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A firecracker shoots up from a hill 160 feet high, with an initial speed of 90 feet per second. Using the formula H(t) = 16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Are there any options with this question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, the options are Five seconds Six seconds Seven seconds Eight seconds

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I can try and help you(:

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0By the way, I'm still here I'm just working on solving it so I can help you.

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Multiply out everything, then move everything over to the right except for "y". If you get something in the form of y = ax^2 + bx + c, where 'a' is not zero, then it's a quadratic equation. 2) Multiply out the right until you get something in the form of y = ax^2 + bx + c, then look at what 'a' would be. 3) y = ax^2 + bx + c is going to be the graph of a parabola. If a > 0, then it opens upwards and the vertex shows the minimum value for y. If a < 0, then it opens downwards, and the vertex shows the maximum value for y. 4) Subtract 24x from both sides, then factor out 8x. 5) See #4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why delete it? I was in the middle of reading it D:

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3i made a typo lol

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3\[\large \text{A firecracker shoots up from a hill } {\color{red}{\text{160 feet high}}},\\ \large\text{with an }{\color{green}{\text{initial speed of 90 feet per second}}}.\\ \large \text{Using the formula } H(t) = 16t^2 + vt + s,\\ \large \text{approximately how long will it take the firecracker to hit the ground?}\] From that info, we can pull out \[\large \text{Initial Height: }{\color{red}{ s = 160}}\] \[\large \text{Initial Velocity: }{\color{green}{ v = 90}}\] So the expression \[\large 16t^2 + {\color{green}{v}}t + {\color{red}{s}}\] turns into \[\large 16t^2 + {\color{green}{90}}t + {\color{red}{160}}\] Hopefully this is making sense so far?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3but it's fixed now

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3From here you need to solve \[\Large 16t^2 + 90t + 160=0\] for t. Use the quadratic formula to do so

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, I can handle it from here. Sorry for the delay, the pizza man came :D

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3That's ok. Let me know what solutions for t you get.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I remember too then I will!
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