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anonymous
 one year ago
Does anyone understand the explination of the costs of elimination. I have both of his books, and different versions, and it is really not clear to me. He is very ambigiuos ...
anonymous
 one year ago
Does anyone understand the explination of the costs of elimination. I have both of his books, and different versions, and it is really not clear to me. He is very ambigiuos ...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In lecture 4 he sad that a n x n matrix has a 1/3*n^3 cost, because the matrix has n*n=n^2 elements. The sum of all the elements from 1^2 =1 to n^2 is (1/3)*n^3 for any n. In calculus you could solve this with integration where you take a function f is n^2, than you integrate function f and an undifinite integral of n^2 is 1/3*n^3.\[\sum_{n=1}^{n}\ n^{2}=\frac{ 1 }{ 3 }*n^{3}\rightarrow \int\limits_{}^{}n^{2} dn= \frac{ n^{3} }{ 3 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0On top of what M.J. said, the meaning of that is that the number of operations that takes to do elimination can be bounded by n^3/3, this means that no matter how much n grows, it will never require more than n^3/3 computations

banda_mohammod_al_helal
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand your question clearly if you mean target of elimination then i say you we do elimination to find the solution of a system.
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