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anonymous

  • one year ago

Thanks for helping! Help with symmetries! Identify, graph, and state the symmetries of each polar equation. Write the scale that you are using for the polar axis. r=9cos(5 theta)

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  1. anonymous
    • one year ago
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    @Hero @jim_thompson5910 @phi @zepdrix @SithsAndGiggles @wio @sleepyjess @Data_LG2

  2. UsukiDoll
    • one year ago
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    cosine is the only even function ( a mirrored symmetry) while tangent and sine are odd functions (symmetry at the origin)

  3. anonymous
    • one year ago
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    It asks me for symmetry about the polar axis, etc.

  4. UsukiDoll
    • one year ago
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    first we need to graph this... you may need to let theta = pi/2, pi , 3pi/2 , 2pi , pi/4, pi/3, pi/6 to figure out your r and graph it (r, theta)

  5. anonymous
    • one year ago
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    Like this?

  6. UsukiDoll
    • one year ago
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    umm let me check in a bit. I am with someone atm

  7. anonymous
    • one year ago
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    ok cool

  8. UsukiDoll
    • one year ago
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    is that desmos?

  9. anonymous
    • one year ago
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    yea

  10. UsukiDoll
    • one year ago
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    cool. so we have a flower in the graph

  11. anonymous
    • one year ago
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    yup

  12. anonymous
    • one year ago
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    I know for a fact it has symmetry about the polar axis

  13. anonymous
    • one year ago
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    but I need help with the rest

  14. UsukiDoll
    • one year ago
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    yeah.. I see a petal on the far right |dw:1434251562785:dw| oh wow my draw is broken

  15. UsukiDoll
    • one year ago
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    that one shows symmetry on that one petal only

  16. anonymous
    • one year ago
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    yup

  17. anonymous
    • one year ago
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    But there was an equation thing for it that I used and it worked.

  18. UsukiDoll
    • one year ago
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    equation thing?

  19. anonymous
    • one year ago
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    since cos is always equal

  20. anonymous
    • one year ago
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    r=9cos(5(-theta))=

  21. anonymous
    • one year ago
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    9cos(-5 theta)

  22. anonymous
    • one year ago
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    9cos(5 theta)

  23. UsukiDoll
    • one year ago
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    and it's also the only even function...

  24. anonymous
    • one year ago
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    yup

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