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anonymous
 one year ago
Combine as indicated by the signs:
4/y^29 + 5/y+3
anonymous
 one year ago
Combine as indicated by the signs: 4/y^29 + 5/y+3

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2do you know how to factor? and take the least common denominator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0...unfortunatly i dont really I'm in the process of teaching myself.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4}{y^29} + \frac{5}{y+3}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2there is a perfect square for the first fraction in the denominator ... a product of some integer with itself. \[y^29\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2in the form of \[(a^2b^2) =(a+b)(ab)\] so if we let a = y^2 and b=9 we need to take the square root of y^2 and the square root of 9. Can you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldnt the square root of y^2 just be y and the square root of 9 is 3?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so since we have a = y and b = 3 we have \[(y^29)=(y+3)(y3) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4}{(y+3)(y3)} + \frac{5}{y+3}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2now noticed how our denominators are different? :O we need to take the lcd.. since lcd is (y+3)(y3) we need to multiply ?????????????? so the denominator in the second fraction is the same as the denominator in the first fraction

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so what is missing in the denominator for the second fraction? I have y+3 but I don't have ?????

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2you're on the right track

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so we multiply y3 on the numerator for the second fraction and multiply y3 on the denominator for the second fraction as well

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4}{(y+3)(y3)} + \frac{5}{y+3} \times \frac{y3}{y3}\] your fraction will look something like this

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4}{(y+3)(y3)} + \frac{5(y3)}{y+3(y3)} \] so we distribute the 5 all over y3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2can you distribute the 5 towards y3 ? it's like multiplying 5 times y and 5 times 3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4}{(y+3)(y3)} + \frac{5y15}{y+3(y3)}\] yes

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{4+5y15}{(y+3)(y3)} \] now we need to compute 415

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{5y11}{(y+3)(y3)}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we can't factor anything out and there's nothing to cancel, so we're done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i got it and can you look at one more problem and tell me why my answer is only partially right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08y/3y + y+2/9y  2/6y i got 2y+23/9y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{8y}{3y}+ \frac{y+2}{9y}\frac{2}{6y}\] this?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok so all of them have y in common but we notice that the denominators are different.. we also notice that the third fraction \[\frac{2}{6}\] can be reduced . can you reduce that fraction for me?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{8y}{3y}+ \frac{y+2}{9y}\frac{1}{3y}\] alright... now we noticed that the first and third fraction has the same denominator, so we can rewrite this fraction and solve . \[\frac{8y}{3y}\frac{1}{3y}+ \frac{y+2}{9y}\] \[\frac{8y1}{3y}+\frac{y+2}{9y}\] can you combine like terms on the first fraction ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we just have to do this arithmetic 8y1 which can be rewritten as y+81

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so what is the answer?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I can't combine variables... but I can combine numbers for y+81

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it just be 1+81/9y?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2no.. leave y alone .. what is 81?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{y+7}{3y}+\frac{y+2}{9y}\] yes.. we still can't add these denominators.. we have the y's so we just need a number so 3 x ? = 9

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{3(y+7)}{9y}+\frac{y+2}{9y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2now distribute the 3 what is 3 times y what is 3 x 7 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{(3y+21)}{9y}+\frac{y+2}{9y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so what is 3y+y what is 21+2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{(3y+y+21+2)}{9y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.223 is correct but for the y portion that's wrong

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2if you're adding a big negative number and a small positive number, your answer should go down.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{(3y+y+23)}{9y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2try again what is 3y+y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2hmmm... let's ignore the y part ... let's just solve 3+1 think of it as... you want to buy something for $3 but you only have $1, how much more do you need to buy that product?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah, but there's one problem... you're $2 in the red in that example, so 2 is the answer

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{(2y+23)}{9y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2you had the correct answer but you forgot the  sign on the 2y.. I highly suggest you practice on adding and subtracting with negative numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i see now that makes more sense and i totally will work on it ha! thanks
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