A funnel is made up of a partial cone and a cylinder as shown in the figure. The maximum amount of liquid that can be in the funnel at any given time is 16.59375π cubic centimeters. Given this information, what is the volume of the partial cone that makes up the top part of the funnel?
15.75π cm3
17.25π cm3
16.33π cm3
12.5π cm3

- anonymous

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- anonymous

The dimensions are 1.5 base, 1.5 beside the base 4 cm height it looks like and 6cm on the top of the circle

- Michele_Laino

please can you make a drawing of your funnel?

- anonymous

How ? It's like
6cm
4cm
1.5 1.5

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## More answers

- anonymous

The 6cm is at the top of the circle

- Michele_Laino

|dw:1434260848319:dw|
like that?

- anonymous

Yes there's a 1.5 inside the square and on the outside

- Michele_Laino

please place your measures on my drawing

- anonymous

6cm in the circle 4cm in the middle, 1.5 in the square and 1.5 on the left side of the square

- Michele_Laino

|dw:1434261034237:dw|

- Michele_Laino

am I right?

- anonymous

Yes

- anonymous

You need another 1.5 on the side of the 1.5

- Michele_Laino

ok! the general formula for volume of a partial cone like this:
|dw:1434261300118:dw|
is:
\[V = \left\{ {\left( {{R^2} + {r^2}} \right) + \sqrt {R \times r} } \right\}\frac{{\pi h}}{3}\]

- Michele_Laino

like this:
|dw:1434261500243:dw|

- anonymous

I don't know the answer it's so hard and this my last question

- anonymous

Yes

- Michele_Laino

sorry I have made an eror the right formula for volume V is:
\[V = \left\{ {\left( {{R^2} + {r^2}} \right) + \sqrt {{R^2} \times {r^2}} } \right\}\frac{{\pi h}}{3}\]

- Michele_Laino

now we have 2 of such partial cones

- anonymous

So what's the answer
15.75pi/cm^3
17.25 pi/cm^3
16.33pi/cm^3
12.5pi/cm^3

- Michele_Laino

I'm sorry, I think that our funnel is like below:
|dw:1434261952973:dw|

- anonymous

This is due in 5 minutes please help!!

- Michele_Laino

Now using may formula above, we can write the volume of our funnel as below:
\[V = \left\{ {\left( {{6^2} + {{1.5}^2}} \right) + \sqrt {{6^2} \times {{1.5}^2}} } \right\}\frac{{\pi h}}{3} + \pi \times {1.5^2}\left( {4 - h} \right) = 16.59375\pi \]
where h is like in my drawing:
|dw:1434262276286:dw|

- Michele_Laino

what is h?

- anonymous

1.5

- anonymous

No h is 4cm

- Michele_Laino

please wait I'm checking my computations

- Michele_Laino

h can not be equal to 4 cm

- anonymous

Text me I can send you a picture of the problem on my laptop 859-550-7140

- Michele_Laino

please make a screeshot of your picture and post it here as a file

- anonymous

I do not know how

- Michele_Laino

use the snipping tool of Microsoft Windows

- Michele_Laino

with that snipping tool you are able to make a screenshot of your drawing, then post it here using the "Attach File" tab

- anonymous

##### 1 Attachment

- anonymous

there you go

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