## anonymous one year ago A funnel is made up of a partial cone and a cylinder as shown in the figure. The maximum amount of liquid that can be in the funnel at any given time is 16.59375π cubic centimeters. Given this information, what is the volume of the partial cone that makes up the top part of the funnel? 15.75π cm3 17.25π cm3 16.33π cm3 12.5π cm3

1. anonymous

The dimensions are 1.5 base, 1.5 beside the base 4 cm height it looks like and 6cm on the top of the circle

2. Michele_Laino

3. anonymous

How ? It's like 6cm 4cm 1.5 1.5

4. anonymous

The 6cm is at the top of the circle

5. Michele_Laino

|dw:1434260848319:dw| like that?

6. anonymous

Yes there's a 1.5 inside the square and on the outside

7. Michele_Laino

8. anonymous

6cm in the circle 4cm in the middle, 1.5 in the square and 1.5 on the left side of the square

9. Michele_Laino

|dw:1434261034237:dw|

10. Michele_Laino

am I right?

11. anonymous

Yes

12. anonymous

You need another 1.5 on the side of the 1.5

13. Michele_Laino

ok! the general formula for volume of a partial cone like this: |dw:1434261300118:dw| is: $V = \left\{ {\left( {{R^2} + {r^2}} \right) + \sqrt {R \times r} } \right\}\frac{{\pi h}}{3}$

14. Michele_Laino

like this: |dw:1434261500243:dw|

15. anonymous

I don't know the answer it's so hard and this my last question

16. anonymous

Yes

17. Michele_Laino

sorry I have made an eror the right formula for volume V is: $V = \left\{ {\left( {{R^2} + {r^2}} \right) + \sqrt {{R^2} \times {r^2}} } \right\}\frac{{\pi h}}{3}$

18. Michele_Laino

now we have 2 of such partial cones

19. anonymous

So what's the answer 15.75pi/cm^3 17.25 pi/cm^3 16.33pi/cm^3 12.5pi/cm^3

20. Michele_Laino

I'm sorry, I think that our funnel is like below: |dw:1434261952973:dw|

21. anonymous

22. Michele_Laino

Now using may formula above, we can write the volume of our funnel as below: $V = \left\{ {\left( {{6^2} + {{1.5}^2}} \right) + \sqrt {{6^2} \times {{1.5}^2}} } \right\}\frac{{\pi h}}{3} + \pi \times {1.5^2}\left( {4 - h} \right) = 16.59375\pi$ where h is like in my drawing: |dw:1434262276286:dw|

23. Michele_Laino

what is h?

24. anonymous

1.5

25. anonymous

No h is 4cm

26. Michele_Laino

please wait I'm checking my computations

27. Michele_Laino

h can not be equal to 4 cm

28. anonymous

Text me I can send you a picture of the problem on my laptop 859-550-7140

29. Michele_Laino

please make a screeshot of your picture and post it here as a file

30. anonymous

I do not know how

31. Michele_Laino

use the snipping tool of Microsoft Windows

32. Michele_Laino

with that snipping tool you are able to make a screenshot of your drawing, then post it here using the "Attach File" tab

33. anonymous

34. anonymous

there you go