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Mindblast3r

  • one year ago

help!

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  1. mindblast3r
    • one year ago
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    \[4\times \sqrt{3}\times \sqrt{3}\]

  2. mindblast3r
    • one year ago
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    is it possible to simplify this?

  3. anonymous
    • one year ago
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    yes

  4. Ehsan18
    • one year ago
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    4 x 3 = 12 3^1/2 x 3^1/2 = 3

  5. anonymous
    • one year ago
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    \[\sqrt{3} * \sqrt{3} = \sqrt{3^{2}}= ?\]

  6. mindblast3r
    • one year ago
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    i don't get what you guys are telling me.

  7. anonymous
    • one year ago
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    here. \[\sqrt{3}*\sqrt{3}=3^{1/2}*3^{1/2}\]

  8. mindblast3r
    • one year ago
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    3.5 * 3.5?

  9. anonymous
    • one year ago
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    and do you understand indices

  10. mindblast3r
    • one year ago
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    no

  11. mindblast3r
    • one year ago
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    never even heard of that

  12. anonymous
    • one year ago
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    \[2^{3}*2^{2}=2^{3}+^{2}\]

  13. mindblast3r
    • one year ago
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    oh yeah i know that.

  14. mindblast3r
    • one year ago
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    exponent laws

  15. anonymous
    • one year ago
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    meaning that when you have same base multiplying each other with different or same power you take one base and sum up the powers .

  16. mindblast3r
    • one year ago
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    ah oh yeah, so 3^1?

  17. anonymous
    • one year ago
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    yap. very correct

  18. mindblast3r
    • one year ago
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    12 is the answer?

  19. anonymous
    • one year ago
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    and we still have 4. so it will be 4*3 =12

  20. anonymous
    • one year ago
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    yes.

  21. mindblast3r
    • one year ago
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    but how did you know to put the 1/2 power for the sqrts of 3s?

  22. anonymous
    • one year ago
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    because \[\sqrt{x}=x ^{1/2}\]

  23. anonymous
    • one year ago
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    its a rule

  24. mindblast3r
    • one year ago
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    oh i get it i think

  25. mindblast3r
    • one year ago
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    because, x is, x * x

  26. anonymous
    • one year ago
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    so also \[\sqrt[3]{8}=8^{1/3}\]

  27. mindblast3r
    • one year ago
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    it's 2 of the same numbers to multiply each other.

  28. mindblast3r
    • one year ago
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    o.O, how?

  29. anonymous
    • one year ago
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    hmmmmm,... want to be busy now. you can fan and medal so that when am back we continue

  30. mindblast3r
    • one year ago
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    ok thanks

  31. anonymous
    • one year ago
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    http://www.mathsteacher.com.au/year10/ch08_indices/01_index_form/Image4419.gif

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