Mindblast3r
  • Mindblast3r
help!
Mathematics
schrodinger
  • schrodinger
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Mindblast3r
  • Mindblast3r
\[4\times \sqrt{3}\times \sqrt{3}\]
Mindblast3r
  • Mindblast3r
is it possible to simplify this?
anonymous
  • anonymous
yes

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Ehsan18
  • Ehsan18
4 x 3 = 12 3^1/2 x 3^1/2 = 3
anonymous
  • anonymous
\[\sqrt{3} * \sqrt{3} = \sqrt{3^{2}}= ?\]
Mindblast3r
  • Mindblast3r
i don't get what you guys are telling me.
anonymous
  • anonymous
here. \[\sqrt{3}*\sqrt{3}=3^{1/2}*3^{1/2}\]
Mindblast3r
  • Mindblast3r
3.5 * 3.5?
anonymous
  • anonymous
and do you understand indices
Mindblast3r
  • Mindblast3r
no
Mindblast3r
  • Mindblast3r
never even heard of that
anonymous
  • anonymous
\[2^{3}*2^{2}=2^{3}+^{2}\]
Mindblast3r
  • Mindblast3r
oh yeah i know that.
Mindblast3r
  • Mindblast3r
exponent laws
anonymous
  • anonymous
meaning that when you have same base multiplying each other with different or same power you take one base and sum up the powers .
Mindblast3r
  • Mindblast3r
ah oh yeah, so 3^1?
anonymous
  • anonymous
yap. very correct
Mindblast3r
  • Mindblast3r
12 is the answer?
anonymous
  • anonymous
and we still have 4. so it will be 4*3 =12
anonymous
  • anonymous
yes.
Mindblast3r
  • Mindblast3r
but how did you know to put the 1/2 power for the sqrts of 3s?
anonymous
  • anonymous
because \[\sqrt{x}=x ^{1/2}\]
anonymous
  • anonymous
its a rule
Mindblast3r
  • Mindblast3r
oh i get it i think
Mindblast3r
  • Mindblast3r
because, x is, x * x
anonymous
  • anonymous
so also \[\sqrt[3]{8}=8^{1/3}\]
Mindblast3r
  • Mindblast3r
it's 2 of the same numbers to multiply each other.
Mindblast3r
  • Mindblast3r
o.O, how?
anonymous
  • anonymous
hmmmmm,... want to be busy now. you can fan and medal so that when am back we continue
Mindblast3r
  • Mindblast3r
ok thanks
anonymous
  • anonymous
http://www.mathsteacher.com.au/year10/ch08_indices/01_index_form/Image4419.gif

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