Solve the inequality 3(x + 1) + 2(x + 2) > 0. a) x < -7/5 b) x > -7/5 c) x < 7/5 d) x > 7/5

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Solve the inequality 3(x + 1) + 2(x + 2) > 0. a) x < -7/5 b) x > -7/5 c) x < 7/5 d) x > 7/5

Mathematics
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\[\huge~\rm~3(x + 1) + 2(x + 2)\] start by solving this part
\[\huge~\rm~3(x+1)\] distribute
x > -7/5

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5x+7>0
That doesn't explain anything .
Step 1: Simplify both sides of the inequality. 5x+7>0 Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7 Step 3: Divide both sides by 5. 5x 5 > −7 5 x> −7 5
Neither does that.
5x/5 > -7/5 x> -7/5
Step 1: Simplify both sides of the inequality. 5x+7>0
Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7
Step 3:Divide both sides by 5. 5x/5 > -7/5 x> -7/5
did tha explain all
Well yea but its copied and pasted :P
http://www.mathpapa.com/algebra-calculator.html
yea i had to make sure my answer right
cuz im doing the same thing
K

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