## anonymous one year ago Solve the inequality 3(x + 1) + 2(x + 2) > 0. a) x < -7/5 b) x > -7/5 c) x < 7/5 d) x > 7/5

1. pooja195

$\huge~\rm~3(x + 1) + 2(x + 2)$ start by solving this part

2. pooja195

$\huge~\rm~3(x+1)$ distribute

3. anonymous

x > -7/5

4. pooja195

5. anonymous

5x+7>0

6. pooja195

That doesn't explain anything .

7. anonymous

Step 1: Simplify both sides of the inequality. 5x+7>0 Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7 Step 3: Divide both sides by 5. 5x 5 > −7 5 x> −7 5

8. pooja195

Neither does that.

9. anonymous

5x/5 > -7/5 x> -7/5

10. anonymous

Step 1: Simplify both sides of the inequality. 5x+7>0

11. anonymous

Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7

12. anonymous

Step 3:Divide both sides by 5. 5x/5 > -7/5 x> -7/5

13. anonymous

did tha explain all

14. pooja195

Well yea but its copied and pasted :P

15. pooja195
16. anonymous

17. anonymous

cuz im doing the same thing

18. pooja195

K