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Destinyyyy

  • one year ago

Needing assistance with "Factor the polynomial using the grouping number method"

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  1. Destinyyyy
    • one year ago
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    4a^2 -7a+3 (4)(3)=12 Product-- --> Sum (-1)(-12)=12--> -13 (-2)(-6)=12 -->-8 (-3)(-4)=12 -->-7 <-- 4a^2 -7a+3= 4a^2 -3a-4a+3 (4a^2 -3a) - (-4a+3) ---Stuck here

  2. pooja195
    • one year ago
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    lets switch it \[\huge~\rm ~(4a^2 --4a) - (3a+3)\]

  3. pooja195
    • one year ago
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    lets switch it \[\huge~\rm ~(4a^2 +4a) - (3a+3)\]

  4. pooja195
    • one year ago
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    now you can solve it :)

  5. Destinyyyy
    • one year ago
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    Why'd you switch it though????? O.o

  6. pooja195
    • one year ago
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    To make it easier to solve

  7. pooja195
    • one year ago
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    it doesnt matter what order you put the a's in

  8. Destinyyyy
    • one year ago
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    Answer-- (a+1)(4a-3)

  9. Destinyyyy
    • one year ago
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    You just switch them around? Theres no minus or plus to cross then to the other side?

  10. pooja195
    • one year ago
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    yes thats right :)

  11. Destinyyyy
    • one year ago
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    Alright I have another one

  12. pooja195
    • one year ago
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    ok repost it :)

  13. Destinyyyy
    • one year ago
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    4x^2 +7x+3 (4)(3)=12 Same product as before (-3)(-4)=12-->-7 4x^2 +7x+3= 4x^2 -3x-4x+3 (4x^2 -3x) - (-4x+3)

  14. pooja195
    • one year ago
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    same thing \[\huge~\rm~(4x^2 -3x) - (-4x+3)\] \[\huge~\rm~(4x^2 +4x) - (-3x+3)\]

  15. Destinyyyy
    • one year ago
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    Answer-- (x+1)(4x-3)

  16. pooja195
    • one year ago
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    somethings wrong..... :L (x+1)(4x-3) (x+1)(4x+3) <--answer

  17. Destinyyyy
    • one year ago
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    Okay!

  18. pooja195
    • one year ago
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    hope i helped :)

  19. Destinyyyy
    • one year ago
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    I got the first one wrong.. Correct answer-- (4a-3)(a-1)

  20. pooja195
    • one year ago
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    It was your math... However switching it does not make a diffrence.

  21. pooja195
    • one year ago
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    But that should have been right.... :/

  22. Destinyyyy
    • one year ago
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    You told me + and a - the correct answer had two - Your switching told me to change the signs. My math was correct till then

  23. pooja195
    • one year ago
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    oh right the signs i think i made a mistake in switching the signs! sorry! :( Did you get the 2nd one right?

  24. Destinyyyy
    • one year ago
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    Yes the second one was correct.. Its fine I still got a 90%

  25. pooja195
    • one year ago
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    hmmm sorry about that its still an A :/ sorry :(

  26. Destinyyyy
    • one year ago
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    Its okay just wish I had check it.. Thank you for your help

  27. pooja195
    • one year ago
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    :)

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