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anonymous
 one year ago
Thanks!
anonymous
 one year ago
Thanks!

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.4we have to apply this formula: \[\Large \frac{{f\left( 7 \right)  f\left( 4 \right)}}{{7  4}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ f(3) }{ 3}\] So it would be?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.4no, you have to substitute the expression of your function, like below: \[\large \begin{gathered} \frac{{f\left( 7 \right)  f\left( 4 \right)}}{{7  4}} = \hfill \\ \hfill \\ = \frac{{\left( {2 \times {7^2}  16 \times 7 + 57} \right)  \left( {2 \times {4^2}  16 \times 4 + 57} \right)}}{3} \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the average rate of change be 6?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I had to plug in 4 and 4 into the original equation, then subtract them from each other and divide it by 3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I meant plug in 7 and 4

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.4you have to plug in 7 and 4, so, the next step is: \[\large \begin{gathered} \frac{{f\left( 7 \right)  f\left( 4 \right)}}{{7  4}} = \hfill \\ \hfill \\ = \frac{{\left( {2 \times {7^2}  16 \times 7 + 57} \right)  \left( {2 \times {4^2}  16 \times 4 + 57} \right)}}{3} = \hfill \\ \hfill \\ = \frac{{  14 + 32}}{3} = ...? \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 18 }{ 3}\] Then simplified to 6?
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