Ehsan18
  • Ehsan18
Find the number of 5-digit numbers that can be formed the digits 1,2,4,6,8 (when no digit is repeated) but, i)the digits 2 and 8 are next to each other ii)the numbers2 and 8 are not next to each other Best and simplest solution gets a medal
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ganeshie8
  • ganeshie8
put 2, 8 in one bag : |dw:1434301423566:dw|
ganeshie8
  • ganeshie8
then you see just \(4\) objects, which can be permuted in \(4!\) ways also 2,8 inside the bag can be permuted in \(2!\) ways for each of the above permutations so total possible 5 digit numbers using the given digits w/o repetition that contain 2,8 together would be \(4!\times 2!\)
Ehsan18
  • Ehsan18
stunning @ganeshie8 what about part ii)? I also found the solution but the method was too long and complicated thanks but please answer the second part too....

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Ehsan18
  • Ehsan18
or is it like 5! - 48?
ganeshie8
  • ganeshie8
that will do for part ii!
Ehsan18
  • Ehsan18
thanks again....
ganeshie8
  • ganeshie8
np:)

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