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Ehsan18

  • one year ago

Find the number of 5-digit numbers that can be formed the digits 1,2,4,6,8 (when no digit is repeated) but, i)the digits 2 and 8 are next to each other ii)the numbers2 and 8 are not next to each other Best and simplest solution gets a medal

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  1. ganeshie8
    • one year ago
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    put 2, 8 in one bag : |dw:1434301423566:dw|

  2. ganeshie8
    • one year ago
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    then you see just \(4\) objects, which can be permuted in \(4!\) ways also 2,8 inside the bag can be permuted in \(2!\) ways for each of the above permutations so total possible 5 digit numbers using the given digits w/o repetition that contain 2,8 together would be \(4!\times 2!\)

  3. Ehsan18
    • one year ago
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    stunning @ganeshie8 what about part ii)? I also found the solution but the method was too long and complicated thanks but please answer the second part too....

  4. Ehsan18
    • one year ago
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    or is it like 5! - 48?

  5. ganeshie8
    • one year ago
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    that will do for part ii!

  6. Ehsan18
    • one year ago
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    thanks again....

  7. ganeshie8
    • one year ago
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    np:)

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