anonymous
  • anonymous
HELP PLEASE WILL MEDAL!!!! What is the standard form of the equation of the circle in the graph? https://prwi7873-stonewall-ccl.gradpoint.com/Resource/5711966,90A,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc093-1.jpg
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Deadpool117
anonymous
  • anonymous
No fuking clue.. sorry kid
anonymous
  • anonymous
Yea.. its pretty hard XD its okay thanks for tryig

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anonymous
  • anonymous
no problem
anonymous
  • anonymous
@acxbox22
anonymous
  • anonymous
@BlossomCake
anonymous
  • anonymous
Ok, I can help. :)
anonymous
  • anonymous
Standard form of a circle is \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] h and k represent the point of the center of the circle and r is the radius.
anonymous
  • anonymous
Yes I know that , I just SUCK at graphs so I have no clue what the h k or r is x.x
anonymous
  • anonymous
"h and k represent the point of the center of the circle and r is the radius." To be a bit clearer, the center point of the circle is (h,k).
anonymous
  • anonymous
so the center of that graph is (-4,0)?
anonymous
  • anonymous
The opposite. It's (0,-4)
anonymous
  • anonymous
oops yea saw that , sorry brain dead when it comes to graphing for some reason XD
anonymous
  • anonymous
x^2+(y-4)^2=16 , is what i think it is
anonymous
  • anonymous
You messed up on 2 points. We're substituting "-4" into (y-k) so it would be (y-(-4) = (y+4). And the radius is 2, so \(2^{2}=4\)
anonymous
  • anonymous
ohhh I see now
anonymous
  • anonymous
one last question c: , I get 17.5 for this am I correct? https://prwi7873-stonewall-ccl.gradpoint.com/Resource/5711966,90A,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc070-1.jpg
anonymous
  • anonymous
No idea.
anonymous
  • anonymous
darn , well ima just take a guess then XD thank you for your help!

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