anonymous
  • anonymous
Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = x − ln 3x, [1/2,2] I got -0.0986.. for the min but i got it wrong, help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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mathstudent55
  • mathstudent55
f(x) = x - ln 3x f'(x) = 1 - 1/x 1 - 1/x = 0 x - 1 = 0 x = 1 Minimum is at x = 1
anonymous
  • anonymous
so my max is wrong too, this is how i was solving it 0.5-ln(1.5) and so on
mathstudent55
  • mathstudent55
Look at the graph of the function. The maximum may be at 0.5 or at 2. Evaluate the function at those two points.

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mathstudent55
  • mathstudent55
You evaluated the function at 0.5, but the maximum may be at another point.
anonymous
  • anonymous
right, and then i did the same for the min and I got-0.098 but when i typed my answer, it said it was wrong 1-ln(3)
mathstudent55
  • mathstudent55
For the minimum, I get it at x = 1.
mathstudent55
  • mathstudent55
When x = 1, f(1) = 1 - ln 3 = -0.0986
mathstudent55
  • mathstudent55
f(1) = 1 - ln 3 is the exact value of the minimum.
anonymous
  • anonymous
yeah and i used -0.0986 for the min, well i rounded so i used -0.10 and it was wrong

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