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anonymous
 one year ago
Find the absolute minimum and absolute maximum values of f on the given interval.
f(x) = x − ln 3x, [1/2,2] I got 0.0986.. for the min but i got it wrong, help!
anonymous
 one year ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = x − ln 3x, [1/2,2] I got 0.0986.. for the min but i got it wrong, help!

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2f(x) = x  ln 3x f'(x) = 1  1/x 1  1/x = 0 x  1 = 0 x = 1 Minimum is at x = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so my max is wrong too, this is how i was solving it 0.5ln(1.5) and so on

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Look at the graph of the function. The maximum may be at 0.5 or at 2. Evaluate the function at those two points.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2You evaluated the function at 0.5, but the maximum may be at another point.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right, and then i did the same for the min and I got0.098 but when i typed my answer, it said it was wrong 1ln(3)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2For the minimum, I get it at x = 1.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2When x = 1, f(1) = 1  ln 3 = 0.0986

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2f(1) = 1  ln 3 is the exact value of the minimum.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah and i used 0.0986 for the min, well i rounded so i used 0.10 and it was wrong
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