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anonymous

  • one year ago

Thanks for helping! Complex conjugate of z2=8(cos(7pi/6)+isin(7pi/6)))

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  1. anonymous
    • one year ago
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    @Hero @Michele_Laino @ganeshie8 @mathstudent55 @Nnesha @Loser66 @Luigi0210 @whpalmer4

  2. anonymous
    • one year ago
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    My worksheet says /z subscript 2. Which I think means complex conjugate.

  3. anonymous
    • one year ago
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    It gave me the z2 equation and just says /z2

  4. anonymous
    • one year ago
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    okay, thanks for attempting to help :)

  5. anonymous
    • one year ago
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    What does the x' and y' mean?

  6. anonymous
    • one year ago
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    oh, gotcha

  7. anonymous
    • one year ago
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    So the conjugate is 2 sqrt(7)?

  8. anonymous
    • one year ago
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    Okay, thanks! That was pretty helpful.

  9. IrishBoy123
    • one year ago
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    *if* \( z_2=8\ (cos\frac {7 \pi}{6} \ + \ isin\frac{7\pi}{6})\), then \( \bar z_2=8\ (cos\frac {7 \pi}{6} \ - \ isin\frac{7\pi}{6})\)

  10. anonymous
    • one year ago
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    Oh, so it only needs a subtraction?

  11. IrishBoy123
    • one year ago
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    @NotSephiroth yes \(z = x + i y\), \(\bar z = x - i y\)

  12. IrishBoy123
    • one year ago
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    or \(z = R e^{i \theta}\), \(\bar z = R e^{-i \theta}\)

  13. anonymous
    • one year ago
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    Okay thanks!

  14. anonymous
    • one year ago
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    that was really helpful!

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