anonymous
  • anonymous
One 10.0 Ω resistor is wired in series with two 5.0 Ω resistors in parallel. A 9.0 V battery supplies power to the circuit. What is the total current through the circuit? A. 0.45 A B. 0.72 A C. 0.87 A D. 1.1 A
Physics
katieb
  • katieb
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Michele_Laino
  • Michele_Laino
here is our circuit: |dw:1434308518619:dw|
anonymous
  • anonymous
ok! what do we do? :/
Michele_Laino
  • Michele_Laino
here the total resistance or equivalent resistance is: \[{R_{TOTAL}} = 10 + \frac{5}{2} = ...Ohms\]

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anonymous
  • anonymous
ok! we get 12.5?
Michele_Laino
  • Michele_Laino
ok!
Michele_Laino
  • Michele_Laino
so , applying the Ohm's law, we get: \[\Large I = \frac{V}{{{R_{TOTAL}}}} = \frac{9}{{12.5}} = ...Amperes\]
anonymous
  • anonymous
0.72! so choice B is our solution?
Michele_Laino
  • Michele_Laino
correct!
anonymous
  • anonymous
yay! thanks!!:)
Michele_Laino
  • Michele_Laino
:):)

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