anonymous one year ago One 10.0 Ω resistor is wired in series with two 5.0 Ω resistors in parallel. A 9.0 V battery supplies power to the circuit. What is the total current through the circuit? A. 0.45 A B. 0.72 A C. 0.87 A D. 1.1 A

1. Michele_Laino

here is our circuit: |dw:1434308518619:dw|

2. anonymous

ok! what do we do? :/

3. Michele_Laino

here the total resistance or equivalent resistance is: ${R_{TOTAL}} = 10 + \frac{5}{2} = ...Ohms$

4. anonymous

ok! we get 12.5?

5. Michele_Laino

ok!

6. Michele_Laino

so , applying the Ohm's law, we get: $\Large I = \frac{V}{{{R_{TOTAL}}}} = \frac{9}{{12.5}} = ...Amperes$

7. anonymous

0.72! so choice B is our solution?

8. Michele_Laino

correct!

9. anonymous

yay! thanks!!:)

10. Michele_Laino

:):)