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anonymous

  • one year ago

In the circuit shown, the greatest voltage drop will occur across which of the following resistors? R1, R2, R3, or R4 ?

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  1. anonymous
    • one year ago
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  2. Michele_Laino
    • one year ago
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    at the first step the equivalent circuit is: |dw:1434309387712:dw| where R_0 is such that: \[\Large {R_0} = \frac{1}{{\frac{1}{{13}} + \frac{1}{{18}}}} = ...\]

  3. anonymous
    • one year ago
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    ok! so we get 7.548 ?

  4. Michele_Laino
    • one year ago
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    ok! R_0=7.55 ohms

  5. anonymous
    • one year ago
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    yay:)

  6. Michele_Laino
    • one year ago
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    now the current is: \[\large I = \frac{V}{{{R_{TOTAL}}}} = \frac{{15}}{{8.5 + 3.2 + 7.55}} = ...\]

  7. anonymous
    • one year ago
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    so we get 0.779?

  8. Michele_Laino
    • one year ago
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    yes! we can round off that result to I=0.78 amperes

  9. anonymous
    • one year ago
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    ok! what does that mean then?

  10. Michele_Laino
    • one year ago
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    now we have the subsequent voltage drop: \[\large \begin{gathered} {V_1} = {R_1}I = 8.5 \times 0.78 = ... \hfill \\ {V_{AB}} = {R_{AB}}I = 7.55 \times 0.78 = ... \hfill \\ {V_4} = {R_4}I = 3.2 \times 0.78 = ... \hfill \\ \end{gathered} \]

  11. Michele_Laino
    • one year ago
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    drops*

  12. Michele_Laino
    • one year ago
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    |dw:1434309867660:dw|

  13. anonymous
    • one year ago
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    ok so we get 6.63; 5.889; 2.496?

  14. Michele_Laino
    • one year ago
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    that's right!

  15. Michele_Laino
    • one year ago
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    now please keep in mind that the voltage drops across R_2 and R_3 are the same, and both of them is equal to 5.889 volts

  16. Michele_Laino
    • one year ago
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    oops...both of them are equal to...

  17. anonymous
    • one year ago
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    meaning that R4 would be the solution? since it is 3.2?

  18. Michele_Laino
    • one year ago
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    the greatest value is 6.63 volts

  19. anonymous
    • one year ago
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    ok what does that mean? :/

  20. Michele_Laino
    • one year ago
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    that means the greatest voltage drop is across the resistor R_1

  21. anonymous
    • one year ago
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    ohh okay:O sorry i got confused a bit! thank you:)

  22. Michele_Laino
    • one year ago
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    :)

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