anonymous
  • anonymous
Solve each quadratic-quadratic system algebraically. Use the quadratic formula when necessary.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I know how to do it, but this step confuses me. How do they remove the 2/3 and go to the second equation? Why are some things multiplied by 3 and some by 2?
anonymous
  • anonymous
I only looked at file eh8epfd.png. The two equations are not the same. Try substituting x with a real number and you'll see the two equations yield different values. It is possible, they want you to solve two sepereate equations?
anonymous
  • anonymous
I know they're not the same. It's two equations called a system of equations.

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anonymous
  • anonymous
Ok. I'll look at it again. For systems of equations I don't think you'll use the quadratic formula.
anonymous
  • anonymous
You can for certain systems, but not that one. I just included that because that's what the question says.
anonymous
  • anonymous
I looked at both attachments 2x^2 - 7x + 3 does not equal 2/3(x-1)^2 + 3 6x^2 - 21x + 9 does not equal 2x^2 -4x + 2 +3 However, to solve the system of equations of the following: 2x^2 - 7x + 3 = 0 & 6x^2 - 21x + 9 = 0 Step 1: You can multiply the first equation by 3 Step 2: You'll see that both equations are the same Can you upload the original question? Something doesn't sound correct.
anonymous
  • anonymous
Here is the question and the answer.
1 Attachment
anonymous
  • anonymous
Ok saw it. I can't reply now, will look at it later.
anonymous
  • anonymous
It's all good, I can figure it out. Thank you for your help.

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