Solve each quadratic-quadratic system algebraically. Use the quadratic formula when necessary.
Stacey Warren - Expert brainly.com
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I know how to do it, but this step confuses me. How do they remove the 2/3 and go to the second equation? Why are some things multiplied by 3 and some by 2?
I only looked at file eh8epfd.png. The two equations are not the same. Try substituting x with a real number and you'll see the two equations yield different values. It is possible, they want you to solve two sepereate equations?
I know they're not the same. It's two equations called a system of equations.
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Ok. I'll look at it again. For systems of equations I don't think you'll use the quadratic formula.
You can for certain systems, but not that one. I just included that because that's what the question says.
I looked at both attachments
2x^2 - 7x + 3 does not equal 2/3(x-1)^2 + 3
6x^2 - 21x + 9 does not equal 2x^2 -4x + 2 +3
However, to solve the system of equations of the following:
2x^2 - 7x + 3 = 0 &
6x^2 - 21x + 9 = 0
Step 1: You can multiply the first equation by 3
Step 2: You'll see that both equations are the same
Can you upload the original question? Something doesn't sound correct.