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anonymous
 one year ago
Solve each quadraticquadratic system algebraically. Use the quadratic formula when necessary.
anonymous
 one year ago
Solve each quadraticquadratic system algebraically. Use the quadratic formula when necessary.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how to do it, but this step confuses me. How do they remove the 2/3 and go to the second equation? Why are some things multiplied by 3 and some by 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I only looked at file eh8epfd.png. The two equations are not the same. Try substituting x with a real number and you'll see the two equations yield different values. It is possible, they want you to solve two sepereate equations?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know they're not the same. It's two equations called a system of equations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. I'll look at it again. For systems of equations I don't think you'll use the quadratic formula.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can for certain systems, but not that one. I just included that because that's what the question says.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I looked at both attachments 2x^2  7x + 3 does not equal 2/3(x1)^2 + 3 6x^2  21x + 9 does not equal 2x^2 4x + 2 +3 However, to solve the system of equations of the following: 2x^2  7x + 3 = 0 & 6x^2  21x + 9 = 0 Step 1: You can multiply the first equation by 3 Step 2: You'll see that both equations are the same Can you upload the original question? Something doesn't sound correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here is the question and the answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok saw it. I can't reply now, will look at it later.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's all good, I can figure it out. Thank you for your help.
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