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anonymous
 one year ago
The current in a solenoid is changed from 1.1 A to 4.4 A. By what factor does the magnitude of the magnetic field inside the solenoid increase?
A. 2
B. 4
C. 0.5
D. 0.25
anonymous
 one year ago
The current in a solenoid is changed from 1.1 A to 4.4 A. By what factor does the magnitude of the magnetic field inside the solenoid increase? A. 2 B. 4 C. 0.5 D. 0.25

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1let's suppose that our solenoid has N turns and its length is L, then the field H inside it is given by the subsequent formula: \[\Large H = {\mu _0}\frac{{NI}}{L},\quad {\mu _0} = 12.56 \times {10^{  6}}Henry/meter\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! so we can write: \[\Large \begin{gathered} {H_1} = {\mu _0}\frac{{N{I_1}}}{L},\quad {H_2} = {\mu _0}\frac{{N{I_2}}}{L} \hfill \\ \hfill \\ \frac{{{H_2}}}{{{H_1}}} = \frac{{{I_2}}}{{{I_1}}} \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! what do we plug in?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and therefore: \[\Large \frac{{{H_2}}}{{{H_1}}} = \frac{{{I_2}}}{{{I_1}}} = \frac{{4.4}}{{1.1}} = ...\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04! so choice B (4) is our solution? :O
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