anonymous
  • anonymous
rationalize the denominanator and simplify:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
@DoShKa_SyRiA @Desireelover
anonymous
  • anonymous
@iSpiffy2wice

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Nnesha
  • Nnesha
like on the other post somebody told u to multiply both top and bottom by the conjugate of the denominator
anonymous
  • anonymous
yes and thn i get lost trying to do that
Nnesha
  • Nnesha
okay so what's the conjugate of the denominator ?
Nnesha
  • Nnesha
ello?
anonymous
  • anonymous
\[\sqrt{a}+2\sqrt{y}\]
Nnesha
  • Nnesha
yes right multiply \[\huge\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] multiply familiar with the foil method ?
anonymous
  • anonymous
kinda not really'
Nnesha
  • Nnesha
|dw:1434317844701:dw| multiply 2nd parentheses by first term of 1st parentheses
Nnesha
  • Nnesha
or hint: \[\huge\rm (x+y)^2 = x^2 +2xy + y^2\] take square of first term take square of 2nd term and then multiply both term by 2
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
do it and let me know what yo uget :-)
Nnesha
  • Nnesha
yes right multiply \[\large\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] both parentheses are the same at the numerator so you can write it as \[\huge\rm \frac{ (\sqrt{a}+2\sqrt{y})^2 }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] same like (x+y)^2
anonymous
  • anonymous
i see

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