anonymous one year ago rationalize the denominanator and simplify:

1. anonymous

2. anonymous

@DoShKa_SyRiA @Desireelover

3. anonymous

@iSpiffy2wice

4. Nnesha

like on the other post somebody told u to multiply both top and bottom by the conjugate of the denominator

5. anonymous

yes and thn i get lost trying to do that

6. Nnesha

okay so what's the conjugate of the denominator ?

7. Nnesha

ello?

8. anonymous

$\sqrt{a}+2\sqrt{y}$

9. Nnesha

yes right multiply $\huge\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }$ multiply familiar with the foil method ?

10. anonymous

kinda not really'

11. Nnesha

|dw:1434317844701:dw| multiply 2nd parentheses by first term of 1st parentheses

12. Nnesha

or hint: $\huge\rm (x+y)^2 = x^2 +2xy + y^2$ take square of first term take square of 2nd term and then multiply both term by 2

13. anonymous

ok

14. Nnesha

do it and let me know what yo uget :-)

15. Nnesha

yes right multiply $\large\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }$ both parentheses are the same at the numerator so you can write it as $\huge\rm \frac{ (\sqrt{a}+2\sqrt{y})^2 }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }$ same like (x+y)^2

16. anonymous

i see