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anonymous

  • one year ago

rationalize the denominanator and simplify:

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @DoShKa_SyRiA @Desireelover

  3. anonymous
    • one year ago
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    @iSpiffy2wice

  4. Nnesha
    • one year ago
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    like on the other post somebody told u to multiply both top and bottom by the conjugate of the denominator

  5. anonymous
    • one year ago
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    yes and thn i get lost trying to do that

  6. Nnesha
    • one year ago
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    okay so what's the conjugate of the denominator ?

  7. Nnesha
    • one year ago
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    ello?

  8. anonymous
    • one year ago
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    \[\sqrt{a}+2\sqrt{y}\]

  9. Nnesha
    • one year ago
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    yes right multiply \[\huge\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] multiply familiar with the foil method ?

  10. anonymous
    • one year ago
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    kinda not really'

  11. Nnesha
    • one year ago
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    |dw:1434317844701:dw| multiply 2nd parentheses by first term of 1st parentheses

  12. Nnesha
    • one year ago
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    or hint: \[\huge\rm (x+y)^2 = x^2 +2xy + y^2\] take square of first term take square of 2nd term and then multiply both term by 2

  13. anonymous
    • one year ago
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    ok

  14. Nnesha
    • one year ago
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    do it and let me know what yo uget :-)

  15. Nnesha
    • one year ago
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    yes right multiply \[\large\rm \frac{ (\sqrt{a} + 2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] both parentheses are the same at the numerator so you can write it as \[\huge\rm \frac{ (\sqrt{a}+2\sqrt{y})^2 }{ (\sqrt{a}-2\sqrt{y})(\sqrt{a}+2\sqrt{y}) }\] same like (x+y)^2

  16. anonymous
    • one year ago
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    i see

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