anonymous
  • anonymous
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = 6x^3 + x^2 + 6x Please help!
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Critical numbers are where the derivative is 0. What did you get for f'(x)?
anonymous
  • anonymous
18x^2+2x+6
anonymous
  • anonymous
ok. so you want to solve 18x^2+2x+6 = 0 using the quadratic formula or some other method

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anonymous
  • anonymous
oh okay!
anonymous
  • anonymous
i got 4+-sqroot(-428)/36
anonymous
  • anonymous
Ok, so √-428 is an imaginary number, so there are no values of x where the derivative is 0, which means there are no critical values.
anonymous
  • anonymous
so my answer would be DNE
anonymous
  • anonymous
yes
anonymous
  • anonymous
thank you!!
anonymous
  • anonymous
you're welcome!

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