anonymous
  • anonymous
Solve. http://static.k12.com/bank_packages/files/media/mathml_ef759e1d2ede6cf06179a8fe33dcb0aeee3b0747_1.gif A. r ≤ –32 B. r ≥ –32 C. r ≤ –2 D. r ≥ –2
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
These are usually pretty easy. It makes it easier if you pretend that the inequality sign is an equal sign, so: \[-\frac{ r }{ 4 }=8\] What would you do to get r by itself?
anonymous
  • anonymous
take the 4 out?
anonymous
  • anonymous
Yes ma'am! How would you do that?

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anonymous
  • anonymous
i dont know :/
anonymous
  • anonymous
Well if you want to cancel out a number, you have to do the opposite. So since its r divided by -4, whats the opposite of division?
anonymous
  • anonymous
multiplication
anonymous
  • anonymous
Mhm! With equations the rule is "what you do to one side you must do to the other. So since we multipy by -4, we have to do the same to the other side. So that gives us \[-\frac{ r }{ 4 }\times-4 = 8(-4)\] \[r= -32\]
anonymous
  • anonymous
Ohh alright, makes more sense to me now, so would it be A?
anonymous
  • anonymous
Now the rule with inequalities, is that if you ever divide or multiply by a negative, then the sign switches directions. So since we had to multiply by -4, the sign switched from \[\le \to \ge \]
anonymous
  • anonymous
So which would it be?
anonymous
  • anonymous
B :)
anonymous
  • anonymous
You got it :)
anonymous
  • anonymous
Thank you !
anonymous
  • anonymous
My pleasure

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