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anonymous
 one year ago
Solve.
http://static.k12.com/bank_packages/files/media/mathml_ef759e1d2ede6cf06179a8fe33dcb0aeee3b0747_1.gif
A.
r ≤ –32
B.
r ≥ –32
C.
r ≤ –2
D.
r ≥ –2
anonymous
 one year ago
Solve. http://static.k12.com/bank_packages/files/media/mathml_ef759e1d2ede6cf06179a8fe33dcb0aeee3b0747_1.gif A. r ≤ –32 B. r ≥ –32 C. r ≤ –2 D. r ≥ –2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These are usually pretty easy. It makes it easier if you pretend that the inequality sign is an equal sign, so: \[\frac{ r }{ 4 }=8\] What would you do to get r by itself?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes ma'am! How would you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well if you want to cancel out a number, you have to do the opposite. So since its r divided by 4, whats the opposite of division?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mhm! With equations the rule is "what you do to one side you must do to the other. So since we multipy by 4, we have to do the same to the other side. So that gives us \[\frac{ r }{ 4 }\times4 = 8(4)\] \[r= 32\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh alright, makes more sense to me now, so would it be A?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now the rule with inequalities, is that if you ever divide or multiply by a negative, then the sign switches directions. So since we had to multiply by 4, the sign switched from \[\le \to \ge \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So which would it be?
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