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- anonymous

Solve.
http://static.k12.com/bank_packages/files/media/mathml_ef759e1d2ede6cf06179a8fe33dcb0aeee3b0747_1.gif
A.
r ≤ –32
B.
r ≥ –32
C.
r ≤ –2
D.
r ≥ –2

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- anonymous

- schrodinger

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- anonymous

These are usually pretty easy. It makes it easier if you pretend that the inequality sign is an equal sign, so: \[-\frac{ r }{ 4 }=8\] What would you do to get r by itself?

- anonymous

take the 4 out?

- anonymous

Yes ma'am! How would you do that?

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- anonymous

i dont know :/

- anonymous

Well if you want to cancel out a number, you have to do the opposite. So since its r divided by -4, whats the opposite of division?

- anonymous

multiplication

- anonymous

Mhm! With equations the rule is "what you do to one side you must do to the other. So since we multipy by -4, we have to do the same to the other side. So that gives us \[-\frac{ r }{ 4 }\times-4 = 8(-4)\]
\[r= -32\]

- anonymous

Ohh alright, makes more sense to me now, so would it be A?

- anonymous

Now the rule with inequalities, is that if you ever divide or multiply by a negative, then the sign switches directions. So since we had to multiply by -4, the sign switched from \[\le \to \ge \]

- anonymous

So which would it be?

- anonymous

B :)

- anonymous

You got it :)

- anonymous

Thank you !

- anonymous

My pleasure

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