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anonymous

  • one year ago

Trig/Pre Cal/identities Where do I start with this? Do not give answer. Just need to know where to start? I am not sure. \( \frac{cos x}{1-sin x}=\frac{1+sin x}{cos x} \) Thank you

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  1. anonymous
    • one year ago
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    I would multiply the left side by \[\frac{ 1 + \sin x }{ 1 + \sin x}\] because \[\cos^2 x = 1 - \sin^2 x\]

  2. anonymous
    • one year ago
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    \( 1- \cot x=\frac{1+\sin x}{\cos x} \) ?

  3. anonymous
    • one year ago
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    Ok, let me work it from there

  4. anonymous
    • one year ago
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    Yep that is it. Thank you!!!!!

  5. anonymous
    • one year ago
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    @peachpi I sent ya a owlbuck too ;-) thanks

  6. anonymous
    • one year ago
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    you're welcome. and thank you for the owlbuck!

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