Trig/Pre Cal/identities Where do I start with this? Do not give answer. Just need to know where to start? I am not sure. \( \frac{cos x}{1-sin x}=\frac{1+sin x}{cos x} \) Thank you

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Trig/Pre Cal/identities Where do I start with this? Do not give answer. Just need to know where to start? I am not sure. \( \frac{cos x}{1-sin x}=\frac{1+sin x}{cos x} \) Thank you

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I would multiply the left side by \[\frac{ 1 + \sin x }{ 1 + \sin x}\] because \[\cos^2 x = 1 - \sin^2 x\]
\( 1- \cot x=\frac{1+\sin x}{\cos x} \) ?
Ok, let me work it from there

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Yep that is it. Thank you!!!!!
@peachpi I sent ya a owlbuck too ;-) thanks
you're welcome. and thank you for the owlbuck!

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