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anonymous
 one year ago
A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is:
H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4
anonymous
 one year ago
A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is: H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first find the amount of moles of NaOH

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i did but it keeps telling me my answer is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats not what i got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The first step is to find the number of moles of NaOH

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.13 mol/L x 0.02773L = 4.688mol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The molar ratio is 1:3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so divide 4.688/3 = 1.563 mol of H3PO4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The last step is to divide the moles by the volume

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01.563mol/0.029 L = 53.9 mol/L

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem :) Don't forget to metal
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