A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is: H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4

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A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is: H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4

Chemistry
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first find the amount of moles of NaOH
do you know how to do that?
yes i did but it keeps telling me my answer is wrong

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what did you get?
thats not what i got
The first step is to find the number of moles of NaOH
0.13 mol/L x 0.02773L = 4.688mol
The molar ratio is 1:3
so divide 4.688/3 = 1.563 mol of H3PO4
The last step is to divide the moles by the volume
1.563mol/0.029 L = 53.9 mol/L
Does that work?
no problem :) Don't forget to metal
*medal

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