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anonymous
 one year ago
Suppose that 4 ≤ f '(x) ≤ 5 for all values of x. What are the minimum and maximum possible values of
f(3) − f(1)? ?≤ f(3) − f(1) ≤?
Im not really sure how to do this, the examples that i have aren't like this one, please help!
anonymous
 one year ago
Suppose that 4 ≤ f '(x) ≤ 5 for all values of x. What are the minimum and maximum possible values of f(3) − f(1)? ?≤ f(3) − f(1) ≤? Im not really sure how to do this, the examples that i have aren't like this one, please help!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 ≤ f '(x) ≤ 5 means the slope of the tangent line is between 4 and 5. The slope of the secant line from 1 to 3 is \[m = \frac{ f(3)f(1) }{ 31 }=\frac{ f(3)f(1) }{ 2 }\] So I think to get your answers you need to solve \[4 ≤\frac{ f(3)f(1) }{ 2 }≤5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would i plug in for f(3) though?

freckles
 one year ago
Best ResponseYou've already chosen the best response.0From your question it looks like you want to solve for f(3)f(1)

freckles
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to undo division an equation... hint multiply by something that un does it

freckles
 one year ago
Best ResponseYou've already chosen the best response.0and this an inequality not an equation but basically works the same way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so i get 8<f(3)f(1)<10
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