- anonymous

PLEASE EXPLAIN
Which of the following polynomials has x+2 as a factor?
A) x^2 +4
B) x^2 -2x +1
C) 2x^2 -2x +1
D)x^3-6x^2+11x-6
E) 2x^2 + 10x^2 +10x -4

- katieb

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- anonymous

is this a flvs Q?

- anonymous

a what Q???

- anonymous

sorry Q=question

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## More answers

- anonymous

I know but fivs Q??
what you mean by that???

- anonymous

Florida virtual school = flvs is this a question off of their site if so can you tell me what number lesson

- anonymous

no it isnt

- anonymous

okay 1 sec

- anonymous

@Romwil this one is kinda giving me problems so I called in some help

- anonymous

- freckles

if x+2 is a factor then x=-2 is a zero
see for which polynomial when you plug in -2, gives you a result of 0

- freckles

I bet one of your choices is a tyoe-o
and I think I know which one :)

- anonymous

which one?

- freckles

Look at your choices and you tell me which one looks like you have like terms.

- freckles

A) x^2 +4
B) x^2 -2x +1
C) 2x^2 -2x +1
D)x^3-6x^2+11x-6
E) 2x^2 + 10x^2 +10x -4
These are the choices you posted...
Do you see a type-o?
Look at the choice that has like terms.

- freckles

Is the last choice really suppose to have so many x^2 's?

- freckles

anyways
I think it should be:
A) x^2 +4
B) x^2 -2x +1
C) 2x^2 -2x +1
D)x^3-6x^2+11x-6
E) 2x^3 + 10x^2 +10x -4
now just evaluate each of those at x=-2
and see which outputs 0
and that will be your answer

- anonymous

None of the polynomials have x+2 as a factor.
Refer to the attached result from the Mathematica 9 program.

##### 1 Attachment

- anonymous

what the heck are you talking about

- anonymous

@freckles you're right

- freckles

this is why one of the choices is a type-o
I think the type-o is in E
because when you replace the x's with -2's in 2x^3+10x^2+10x-4
you get???

- anonymous

I plugged -2 in all of them and E was the answer, and that's the correct answer
there's no tyop

- anonymous

I get 0

- freckles

right
but there was a type-o @Romwil in the original question

- freckles

you have 2x^2+10x^2+10x-4

- freckles

as choice E

- anonymous

I guess

- anonymous

but either or that's how you solve it right?

- freckles

yep you just look for which outputs 0 for x=-2
that is how you solve it (or I believe is the quickest way anyways)

- freckles

it isn't the only way
just the quickest in my opinion

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