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anonymous
 one year ago
Pre Calc Help
anonymous
 one year ago
Pre Calc Help

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KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2do want to know how or the answer??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know it is steepness but idk the exact rule

KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2yes but it would take a little

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just need someone to explain how i know A based off looking at graph i know its negative but how do i know if its 1,2, etc

KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2alright, so f(x)=(x1)^2+4, does it make sense why

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you give it in standard form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and no im not sure how you got that

KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2okay so since we know the vertext, we know how much to shift it, up four and to the right 1, so thats how i got that

KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2to get the form you want, factor and simplfy it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait so if that was a steeper parabola what would you change

KaiserTheSlayer
 one year ago
Best ResponseYou've already chosen the best response.2the a and for the answer it is 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where is a in the formula you gave me?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright you can find vertex point by looking at the graph right then substitute into this equation \[\huge\rm y = a(xh)^2 +k\] vertex form of quadratic equation after that pick x and y values plug in solve for a :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1and by looking at the shape of graph u can easily find if a is negative or positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0correction no,x=1 and x=3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @MathMan77 where is a in the formula you gave me? \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @KaiserTheSlayer alright, so f(x)=(x1)^2+4, does it make sense why \(\color{blue}{\text{End of Quote}}\) \[y=(x1)^2+4\]  >\[\huge\rm y = \color{red}{a}(xh)^2 +k\] invisble one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Nnesha alright you can find vertex point by looking at the graph right then substitute into this equation \[\huge\rm y = a(xh)^2 +k\] vertex form of quadratic equation after that pick x and y values plug in solve for a :) \(\color{blue}{\text{End of Quote}}\) vertex point ( 1,4) (x,y) (0,3) \[\large\rm 3=a(01)^2 +4\] like this if u solve for a u will get the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=(x+1)(x3)=(x^22x3)=(x^22x)+3=(x^22x+11)+3=(x^22x+1)+1+3 =(x1)^2+4
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