anonymous
  • anonymous
please HELP me i will medal and fan.. The table below shows two equations: Equation 1 |3x − 1| + 7 = 2 Equation 2 |2x + 1| + 4 = 3 Which statement is true about the solution to the two equations? Equation 1 and equation 2 have no solutions. Equation 1 has no solution and equation 2 has solutions x = 0, 1. The solutions to equation 1 are x = −1.3, 2 and equation 2 has no solution. The solutions to equation 1 are x = −1.3, 2 and equation 2 has solutions x = 0, 1.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
I THINK THAT IT IS D?!
anonymous
  • anonymous
Do you know the steps for solving absolute vale equations?
anonymous
  • anonymous
No not really

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anonymous
  • anonymous
Ok.
anonymous
  • anonymous
you set the absolute value side equal to the other side as a Case #1. and set the absolute value side equal to the other side all times -1 as a Case #2
anonymous
  • anonymous
also, absolute value can never get to be negative
anonymous
  • anonymous
the answer has to be the third one
anonymous
  • anonymous
just by deduction
anonymous
  • anonymous
you don't even have to solve :)
anonymous
  • anonymous
hope this helps
anonymous
  • anonymous
Yes, but why is there no solution? there is always a solution
anonymous
  • anonymous
\[\left| -3 \right|= 3\] so the \[\left| x \right|= 3\] means that x could be -3 or positive 3
anonymous
  • anonymous
ok.. thanks!!
anonymous
  • anonymous
to solve for absolute values you need to write it as a positive value as well as a negative value \[\left| 3x-1 \right|+7 =2\]can be re-written as 3x - 1 + 7 = 2, 3x = -4, x = -4/3 = -1.33 and -(3x - 1) + 7 = 2 = -3x + 1 + 7 =2 -3x +8 = 2 -3x = -6 x = 2 Does this make sense?
anonymous
  • anonymous
Try following the same steps for the second equation \[\left| 2x + 1 \right| + 4 = 3\] If you post your work I'll help you through it.

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