• anonymous
In the past, Fred has made four out of every five free throws in basketball that he has attempted. What is the probability that Fred will make the next two free throws he attempts?
  • chestercat
I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this
and thousands of other questions

  • anonymous
To find probability of something (in this case successful free throws), take the number of times that has happened and divide it by the number of chances it had to happen.
  • kropot72
The probability of making one throw is 4/5 = 0.8. The probability of making the next two free throws is given by \[\large P(making\ 2\ successive\ throws)=0.8\times0.8 = you\ can\ calculate\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.