## anonymous one year ago Help with radicals

1. anonymous

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2. anonymous

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3. anonymous

$\sqrt{\frac{ 9 }{ 28 }}$ is the same $\frac{ \sqrt{9} }{ \sqrt{28} }$ do you know how to solve $\sqrt{9}$ and $\sqrt{28}$ ?

4. anonymous

I forgot to add the negative sign

5. anonymous

@LeibyStrauss No can you explain further?

6. anonymous

radical 9, is the same as the square root of 9. Square root and radical mean: what number when multiplied by itself equals x. For example, what is the square root of 4? is asking what number multiplied by itself = 4? The answer is 2 because 2*2 = 4. What is the square root of 9 is asking what number multiplied by itself = 9? Post the answer and I'll help you through the square root of 28

7. anonymous

@LeibyStrauss the square root of 9 is 3*3

8. anonymous

28 (7*2*2)

9. anonymous

$\sqrt{28} = \sqrt{4*7}$ Can you simplify it?

10. anonymous

@LeibyStrauss yes 7*2*2

11. anonymous

$-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ \sqrt{9} }{ \sqrt{28} }= -\frac{ 3 }{ \sqrt{4*7}}$

12. anonymous

13. anonymous

Good. Since the square root of 4 is 2. $\sqrt{4*7}=2\sqrt{7}$ Are you ok now with the final answer?

14. anonymous

@LeibyStrauss I multiplied 3*2 and got 6rad7

15. anonymous

3 will stay in the numerator, and the denominator will be 4 radical 7. Your final answer is $-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ 3 }{ 2\sqrt{7} }$ In a post 10 minutes ago I wrote this out with more steps

16. anonymous

I made a typo in previous post. I meant to write "3 will stay in the numerator and the denominator stays "2" radical 7"

17. anonymous

@LeibyStrauss oh ok my mistake I get it thanks