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anonymous

  • one year ago

Help with radicals

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  1. anonymous
    • one year ago
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    |dw:1434328393781:dw|

  2. anonymous
    • one year ago
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    |dw:1434328458276:dw|

  3. anonymous
    • one year ago
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    \[\sqrt{\frac{ 9 }{ 28 }}\] is the same \[\frac{ \sqrt{9} }{ \sqrt{28} }\] do you know how to solve \[\sqrt{9}\] and \[\sqrt{28}\] ?

  4. anonymous
    • one year ago
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    I forgot to add the negative sign

  5. anonymous
    • one year ago
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    @LeibyStrauss No can you explain further?

  6. anonymous
    • one year ago
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    radical 9, is the same as the square root of 9. Square root and radical mean: what number when multiplied by itself equals x. For example, what is the square root of 4? is asking what number multiplied by itself = 4? The answer is 2 because 2*2 = 4. What is the square root of 9 is asking what number multiplied by itself = 9? Post the answer and I'll help you through the square root of 28

  7. anonymous
    • one year ago
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    @LeibyStrauss the square root of 9 is 3*3

  8. anonymous
    • one year ago
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    28 (7*2*2)

  9. anonymous
    • one year ago
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    \[\sqrt{28} = \sqrt{4*7}\] Can you simplify it?

  10. anonymous
    • one year ago
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    @LeibyStrauss yes 7*2*2

  11. anonymous
    • one year ago
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    \[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ \sqrt{9} }{ \sqrt{28} }= -\frac{ 3 }{ \sqrt{4*7}}\]

  12. anonymous
    • one year ago
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    @LeibyStrauss I got 6rad7

  13. anonymous
    • one year ago
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    Good. Since the square root of 4 is 2. \[\sqrt{4*7}=2\sqrt{7}\] Are you ok now with the final answer?

  14. anonymous
    • one year ago
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    @LeibyStrauss I multiplied 3*2 and got 6rad7

  15. anonymous
    • one year ago
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    3 will stay in the numerator, and the denominator will be 4 radical 7. Your final answer is \[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ 3 }{ 2\sqrt{7} }\] In a post 10 minutes ago I wrote this out with more steps

  16. anonymous
    • one year ago
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    I made a typo in previous post. I meant to write "3 will stay in the numerator and the denominator stays "2" radical 7"

  17. anonymous
    • one year ago
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    @LeibyStrauss oh ok my mistake I get it thanks

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