anonymous
  • anonymous
Help with radicals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1434328393781:dw|
anonymous
  • anonymous
|dw:1434328458276:dw|
anonymous
  • anonymous
\[\sqrt{\frac{ 9 }{ 28 }}\] is the same \[\frac{ \sqrt{9} }{ \sqrt{28} }\] do you know how to solve \[\sqrt{9}\] and \[\sqrt{28}\] ?

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anonymous
  • anonymous
I forgot to add the negative sign
anonymous
  • anonymous
@LeibyStrauss No can you explain further?
anonymous
  • anonymous
radical 9, is the same as the square root of 9. Square root and radical mean: what number when multiplied by itself equals x. For example, what is the square root of 4? is asking what number multiplied by itself = 4? The answer is 2 because 2*2 = 4. What is the square root of 9 is asking what number multiplied by itself = 9? Post the answer and I'll help you through the square root of 28
anonymous
  • anonymous
@LeibyStrauss the square root of 9 is 3*3
anonymous
  • anonymous
28 (7*2*2)
anonymous
  • anonymous
\[\sqrt{28} = \sqrt{4*7}\] Can you simplify it?
anonymous
  • anonymous
@LeibyStrauss yes 7*2*2
anonymous
  • anonymous
\[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ \sqrt{9} }{ \sqrt{28} }= -\frac{ 3 }{ \sqrt{4*7}}\]
anonymous
  • anonymous
@LeibyStrauss I got 6rad7
anonymous
  • anonymous
Good. Since the square root of 4 is 2. \[\sqrt{4*7}=2\sqrt{7}\] Are you ok now with the final answer?
anonymous
  • anonymous
@LeibyStrauss I multiplied 3*2 and got 6rad7
anonymous
  • anonymous
3 will stay in the numerator, and the denominator will be 4 radical 7. Your final answer is \[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ 3 }{ 2\sqrt{7} }\] In a post 10 minutes ago I wrote this out with more steps
anonymous
  • anonymous
I made a typo in previous post. I meant to write "3 will stay in the numerator and the denominator stays "2" radical 7"
anonymous
  • anonymous
@LeibyStrauss oh ok my mistake I get it thanks

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