Help with radicals

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Help with radicals

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\sqrt{\frac{ 9 }{ 28 }}\] is the same \[\frac{ \sqrt{9} }{ \sqrt{28} }\] do you know how to solve \[\sqrt{9}\] and \[\sqrt{28}\] ?

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I forgot to add the negative sign
@LeibyStrauss No can you explain further?
radical 9, is the same as the square root of 9. Square root and radical mean: what number when multiplied by itself equals x. For example, what is the square root of 4? is asking what number multiplied by itself = 4? The answer is 2 because 2*2 = 4. What is the square root of 9 is asking what number multiplied by itself = 9? Post the answer and I'll help you through the square root of 28
@LeibyStrauss the square root of 9 is 3*3
28 (7*2*2)
\[\sqrt{28} = \sqrt{4*7}\] Can you simplify it?
@LeibyStrauss yes 7*2*2
\[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ \sqrt{9} }{ \sqrt{28} }= -\frac{ 3 }{ \sqrt{4*7}}\]
@LeibyStrauss I got 6rad7
Good. Since the square root of 4 is 2. \[\sqrt{4*7}=2\sqrt{7}\] Are you ok now with the final answer?
@LeibyStrauss I multiplied 3*2 and got 6rad7
3 will stay in the numerator, and the denominator will be 4 radical 7. Your final answer is \[-\sqrt{\frac{ 9 }{ 28 }}= -\frac{ 3 }{ 2\sqrt{7} }\] In a post 10 minutes ago I wrote this out with more steps
I made a typo in previous post. I meant to write "3 will stay in the numerator and the denominator stays "2" radical 7"
@LeibyStrauss oh ok my mistake I get it thanks

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