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anonymous
 one year ago
help with radicals
anonymous
 one year ago
help with radicals

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@LeibyStrauss dw:1434330140647:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434330297233:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{588v^3w^4}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1shall we start on the exponents? it's easier

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1let's start at the fact that we are just dealing with square root so anything even will be square rooted quite nicely. let's start at the \[w^4\] now.. \[\sqrt{w^4}\] can also be written in exponential form, but since we are not dealing with cube root, square root is 2 and it's not written (that's normal) in the form of dw:1434330705533:dw \[w^{4/2} \] so what is 4/2 for w ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yay! now let's deal with \[\sqrt{v^3}\] we can actually split the exponent up using one of the exponent laws \[v^{a}v^{b}\] for \[v^3 \rightarrow v^2v\] so \[\sqrt{v^2v}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so which one stays in the radical? anything not divisible by 2 stays in the radical . What is the square root of v^2?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1what is \[\sqrt{v^2}\] focus on that part only... we can't take square root of v

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1waitttttt.... \[\sqrt{v^3} \] you an split this up \[\sqrt{v^2v}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1you can take the square root of the v^2 but not the v. so while the only v stays in the radical, you can take the square root of v^2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{588v^2v(}w^2)\] this is what we have so far.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1you can split any odd exponent number up in two.. like for example \[\sqrt{y^5} \rightarrow \sqrt{y^4y} \rightarrow y^2\sqrt{y}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1for square roots we want even exponent numbers... for cube roots we want certain exponent numbers

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1anyway, now can you tell me what \[\sqrt{v^2v} \] is ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{v^3} \rightarrow \sqrt{v^2}{v} > ?????\] \[\sqrt{v^2} \rightarrow v^{\frac{2}{2}}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1square root of v is fine, but that v^2 isn't... I have rewritten it in exponential form what is 2/2 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah you will have just a v

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{588v(}w^2v)\] v to the first power or just v

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1now we have this nasty big number.. we need to not only split this in two but we need the largest perfect square number

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1otherwise you will be taking radicals over and over again and that takes a lot of time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll ok how do we do that

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1perfect square numbers are like 9 16 25 4 36

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah that works... but we may need to take the radical again for 12 ... eh shouldn't be too bad

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{49 \times 12 [v]} (w^2v)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1what is the square root of 49 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{12 [v]} (7w^2v) \rightarrow \sqrt{(4)(3)[v]} (7vw^2)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1mhm now we already have 12 = 4 x 3 so what's the square root of 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{(3)[v]} (7(2)vw^2)\] we are almost done. we just need to combine 7 and 2.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{3v} (14vw^2)\] yup so this is your final answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldnt the 14vw^2 would go outside

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1:) I'm just rechecking with wolfram alpha , but this time I don't agree with it . the stupid calculator didn't simplify the w^4 in the square root... it is outside... the square root is just 3v. everything in the () represented outside.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes what we did manually is correct... wolfram alpha is making me mad on that v^3 part . the exponent is greater than 2 and can be split up. Wolfram says leave it alone (WRONG!) but purplemath says split it up. http://www.purplemath.com/modules/radicals2.htm see the example with the 12abc

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1the c^3 in that example has been split up to c^2 (c) then that c is left in the radical and the square root of c^2 is taken.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1wolfram can be sketchy at times... some users on here proven that ultimate calculator to be wrong several times. It shows that not everything is reliable... just focus on the purplemath site and what we did. splitting it up was the right thing to do because that's how I remembered it a long time ago.
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