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## anonymous one year ago Help with radicals

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1. anonymous

|dw:1434332461177:dw|

2. anonymous

thats a 12 btw

3. anonymous

@LeibyStrauss @UsukiDoll

4. anonymous

@Nnesha

5. anonymous

@badmood @puppylover0617

6. anonymous

How can you factor $\sqrt{4x+12}$ so that it is simplified?

7. anonymous

@LeibyStrauss rad2x+4*3?

8. anonymous

Solve the following $\frac{ \sqrt{4x} }{ 4 } + \frac{ \sqrt{12} }{ 4 }$

9. anonymous

@LeibyStrauss 2x/4+4*3/4?

10. anonymous

I don't know where your getting the 2x from. You may have the correct answer, but I'm not understanding what is written. What is 4/4 What is 12/4

11. anonymous

@LeibyStrauss 1 3

12. anonymous

1,3

13. anonymous

@tysonw do you know how to factor (4x + 12)

14. anonymous

Good. How would you re-write Peachpi's example with 1x + 3 in parenthesis but has the same value as 4x + 12?

15. anonymous

@LeibyStrauss I HAVE NO IDEA CAN YOU SHOW LOL

16. anonymous

sorry for the caps

17. anonymous

|dw:1434335668717:dw|

18. anonymous

$4(x+3)$ x is the same as 1x so 4*1x or 4*x = 4x and 4*3 =12 Re-write the radical equation in the same format. For example $\sqrt{4x +16} = 4\sqrt{x +4}$

19. anonymous

4(x+3)?

20. anonymous

yes

21. anonymous

You are correct!

22. anonymous

|dw:1434335919961:dw|

23. anonymous

2

24. anonymous

I think you meant to write 4 without the radical

25. anonymous

It should be $4\sqrt{x+3}+\sqrt{x+3}$ Nod you need to combine like terms

26. anonymous

So you have $2 \sqrt{x+3}+1\sqrt{x+3}$ You can treat $\sqrt{x+3}$ as a variable, so they combine

27. anonymous

@LeibyStrauss no you have to take the square root of the 4 because it's under the radical

28. anonymous

@peachpi @LeibyStrauss Ok thanks!

29. anonymous

I stand corrected. So the correct way is $\sqrt{4(x+3)}= 2\sqrt{x+3}$

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