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anonymous

  • one year ago

Help with radicals

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  1. anonymous
    • one year ago
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    |dw:1434332461177:dw|

  2. anonymous
    • one year ago
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    thats a 12 btw

  3. anonymous
    • one year ago
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    @LeibyStrauss @UsukiDoll

  4. anonymous
    • one year ago
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    @Nnesha

  5. anonymous
    • one year ago
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    @badmood @puppylover0617

  6. anonymous
    • one year ago
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    How can you factor \[\sqrt{4x+12}\] so that it is simplified?

  7. anonymous
    • one year ago
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    @LeibyStrauss rad2x+4*3?

  8. anonymous
    • one year ago
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    Solve the following \[\frac{ \sqrt{4x} }{ 4 } + \frac{ \sqrt{12} }{ 4 }\]

  9. anonymous
    • one year ago
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    @LeibyStrauss 2x/4+4*3/4?

  10. anonymous
    • one year ago
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    I don't know where your getting the 2x from. You may have the correct answer, but I'm not understanding what is written. What is 4/4 What is 12/4

  11. anonymous
    • one year ago
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    @LeibyStrauss 1 3

  12. anonymous
    • one year ago
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    1,3

  13. anonymous
    • one year ago
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    @tysonw do you know how to factor (4x + 12)

  14. anonymous
    • one year ago
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    Good. How would you re-write Peachpi's example with 1x + 3 in parenthesis but has the same value as 4x + 12?

  15. anonymous
    • one year ago
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    @LeibyStrauss I HAVE NO IDEA CAN YOU SHOW LOL

  16. anonymous
    • one year ago
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    sorry for the caps

  17. anonymous
    • one year ago
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    |dw:1434335668717:dw|

  18. anonymous
    • one year ago
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    \[4(x+3)\] x is the same as 1x so 4*1x or 4*x = 4x and 4*3 =12 Re-write the radical equation in the same format. For example \[\sqrt{4x +16} = 4\sqrt{x +4}\]

  19. anonymous
    • one year ago
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    4(x+3)?

  20. anonymous
    • one year ago
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    yes

  21. anonymous
    • one year ago
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    You are correct!

  22. anonymous
    • one year ago
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    |dw:1434335919961:dw|

  23. anonymous
    • one year ago
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    2

  24. anonymous
    • one year ago
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    I think you meant to write 4 without the radical

  25. anonymous
    • one year ago
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    It should be \[4\sqrt{x+3}+\sqrt{x+3}\] Nod you need to combine like terms

  26. anonymous
    • one year ago
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    So you have \[2 \sqrt{x+3}+1\sqrt{x+3}\] You can treat \[\sqrt{x+3}\] as a variable, so they combine

  27. anonymous
    • one year ago
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    @LeibyStrauss no you have to take the square root of the 4 because it's under the radical

  28. anonymous
    • one year ago
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    @peachpi @LeibyStrauss Ok thanks!

  29. anonymous
    • one year ago
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    I stand corrected. So the correct way is \[\sqrt{4(x+3)}= 2\sqrt{x+3}\]

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