anonymous
  • anonymous
Help with radicals
Mathematics
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anonymous
  • anonymous
Help with radicals
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
|dw:1434336375394:dw|
anonymous
  • anonymous
anonymous
  • anonymous
do you know what the conjugate is?

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anonymous
  • anonymous
@peachpi Idk what that is
anonymous
  • anonymous
can you explain
anonymous
  • anonymous
the conjugate is where you change the sign of the radical in the denominator and multiply by it to get rid of the square root in the denominator. Your denominator is 9-√5, so the conjugate is 9+√5. So to solve your problem you need to simplify this |dw:1434336787389:dw|
anonymous
  • anonymous
@peachpi ok than what would be next?
anonymous
  • anonymous
|dw:1434337068377:dw|
anonymous
  • anonymous
the top is right. FOIL the bottom
UsukiDoll
  • UsukiDoll
the first part of the denominator is right... second part... no because when we are multiply square roots it's just that number
UsukiDoll
  • UsukiDoll
for example \[(\sqrt{3})(\sqrt{3}) = 3\] now apply that example to your problem
anonymous
  • anonymous
@UsukiDoll I'm lost so how would the denominator look?
UsukiDoll
  • UsukiDoll
\[(9-\sqrt{5})(9+\sqrt{5})\] is your denominator .. use foil.. the O and I cancels out
anonymous
  • anonymous
so it would be 81+5?
anonymous
  • anonymous
yes
UsukiDoll
  • UsukiDoll
then just add 81+5
anonymous
  • anonymous
ok thanks

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