Choose the equation below that represents the line passing through the point (2, -5) with a slope of -3. y = -3x - 13 y = -3x + 11 y = -3x + 13 y = -3x + 1

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Choose the equation below that represents the line passing through the point (2, -5) with a slope of -3. y = -3x - 13 y = -3x + 11 y = -3x + 13 y = -3x + 1

Mathematics
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The general slope intercept form is y = mx+b the m is the slope (think "m" for mountain, mountains have slopes) since the slope is -3, we know that m = -3 so the equation is in the form y = -3x + b
the line passes through (2,-5) (x,y) = (2,-5) x = 2 y = -5 y = -3x + b y = -3*2 + b ... replace x with 2 y = -6 + b -5 = -6 + b ... replace y with -5 now solve for b

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now how would I do that, I don't quite get how to solve for b.
think of -6+b as b-6
-5 = b-6 try to move that -6 over to isolate b
have b by itself.. what do you need to do to make this happen?
subtract -6 from the sides?
close
oh nvm, I was thinking of something else yeah you are correct
subtracting -6 from both sides is the same as adding 6 to both sides
|dw:1434337014605:dw|
|dw:1434337031428:dw|
|dw:1434337050301:dw|
oh okay
Now what? @jim_thompson5910
now evaluate the left side in the drawing below |dw:1434337318985:dw|
|dw:1434337345417:dw|
+ 1
so b = 1
m = -3 was the given slope b = 1 is the y-intercept we just found out
you would plug those into y = mx+b
so it would be y = -3x + 1 ?
correct
Yay!! Thanks ^-^
np

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