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anonymous

  • one year ago

A straight 1.2 m length iron rod is moved at 10 m/s through the earth's magnetic field at a location where it has magnitude 1.0 × 10^-5 T. What is the magnitude of the induced emf between one end of the wire and the other end? A. 1.2 V B. 1.2 × 10^-4 V C. 1.0 × 10^-4 V D. 120 V

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  1. Michele_Laino
    • one year ago
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    I'm pondering...

  2. anonymous
    • one year ago
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    ok!

  3. Michele_Laino
    • one year ago
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    during the motion of that iron rod, an electric field will appear inside that iron rod, since all free electrons inside that rod are underwent to the Lorentz force. Now the motion of such free electrons will terminate when the Lorentz force is balanced with the resultant electrostatic force. The situation is as below: |dw:1434343667110:dw|

  4. anonymous
    • one year ago
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    yes:)

  5. Michele_Laino
    • one year ago
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    so we can write: \[\Large evB = e\frac{V}{L}\] where V is the emf force, and v is the velocity of the iron rod after a simplification we get: \[\Large V = vBL\]

  6. Michele_Laino
    • one year ago
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    L is the length of the iron rod

  7. anonymous
    • one year ago
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    ok! what do we plug in?

  8. Michele_Laino
    • one year ago
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    here is the next step: \[\Large V = vBL = 10 \times {10^{ - 5}} \times 1.2 = ...volts\]

  9. anonymous
    • one year ago
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    ok! we get 1.2E-4? so choice B is our solution? :O

  10. Michele_Laino
    • one year ago
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    that's right!

  11. anonymous
    • one year ago
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    ooh yay! thanks:)

  12. Michele_Laino
    • one year ago
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    :)

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