anonymous
  • anonymous
A straight 1.2 m length iron rod is moved at 10 m/s through the earth's magnetic field at a location where it has magnitude 1.0 × 10^-5 T. What is the magnitude of the induced emf between one end of the wire and the other end? A. 1.2 V B. 1.2 × 10^-4 V C. 1.0 × 10^-4 V D. 120 V
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Michele_Laino
  • Michele_Laino
I'm pondering...
anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
during the motion of that iron rod, an electric field will appear inside that iron rod, since all free electrons inside that rod are underwent to the Lorentz force. Now the motion of such free electrons will terminate when the Lorentz force is balanced with the resultant electrostatic force. The situation is as below: |dw:1434343667110:dw|

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anonymous
  • anonymous
yes:)
Michele_Laino
  • Michele_Laino
so we can write: \[\Large evB = e\frac{V}{L}\] where V is the emf force, and v is the velocity of the iron rod after a simplification we get: \[\Large V = vBL\]
Michele_Laino
  • Michele_Laino
L is the length of the iron rod
anonymous
  • anonymous
ok! what do we plug in?
Michele_Laino
  • Michele_Laino
here is the next step: \[\Large V = vBL = 10 \times {10^{ - 5}} \times 1.2 = ...volts\]
anonymous
  • anonymous
ok! we get 1.2E-4? so choice B is our solution? :O
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
ooh yay! thanks:)
Michele_Laino
  • Michele_Laino
:)

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