## anonymous one year ago A coil with an area of 0.10 m^2 is in a magnetic field of 0.20 T perpendicular to its area. It is flipped through 180° so that the part that was up is down. The flip takes 1.0 s. Estimate the average induced emf between the ends of the coil while it is being flipped. A. 0.020 V B. 0.040 V c. 0.0 V D. 0.010 V

1. anonymous

2. Michele_Laino

here the magnetic flux change is: $\Large \begin{gathered} \Delta \Phi = \Phi \left( {\mathbf{B}} \right) - \Phi \left( { - {\mathbf{B}}} \right) = 2\Phi \left( {\mathbf{B}} \right) = \hfill \\ \hfill \\ = 2 \times 0.10 \times 0.20 = ...Weber \hfill \\ \end{gathered}$

3. anonymous

we get 0.04?so choice B? :O

4. Michele_Laino

no, since we have to compute the emf, which is given by the subsequent formula: $\Large E = \frac{{\Delta \Phi }}{{\Delta t}} = \frac{{0.04}}{1} = ...volts$

5. anonymous

ohh okay! that still gets 0.04 though? :/

6. Michele_Laino

yes! that's right!

7. anonymous

yay! thanks!!:D

8. Michele_Laino

:)