anonymous
  • anonymous
In a chemistry technique known as flame photometry, a sample gets burned in a high-temperature flame, and the amount of light at a specific wavelength is measured to identify the elements within the sample. Which of the following is this technique based upon? A. emission spectra B. absorption spectra C. continuous spectra D. noncontinuous spectra
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Michele_Laino
  • Michele_Laino
I'm pondering...
anonymous
  • anonymous
ok! :)
Michele_Laino
  • Michele_Laino
I think emission spectra, namely option A

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ohhh okay! thank you!:D
rvc
  • rvc
@Michele_Laino is awesome :)
anonymous
  • anonymous
i have to agree with that @rvc :) you rock @Michele_Laino !!:D
Michele_Laino
  • Michele_Laino
more explanation: the flame gives energy to tha atoms of the substance, and those atoms go into an excited quantum state, now that state is temporary, so it will disappear. In doing so the electrons will communicate the absorbed quantums of light by means of emission spectra
anonymous
  • anonymous
ahh okie! thank you!:D
Michele_Laino
  • Michele_Laino
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.