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anonymous
 one year ago
fg is perpendicular to op, rs is perpendicular to oq, fg=32, rs=39 and op=14. find the value of x
anonymous
 one year ago
fg is perpendicular to op, rs is perpendicular to oq, fg=32, rs=39 and op=14. find the value of x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434347870486:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a). 19.5 b). 20.8 c). 14 d). 8.5

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2wow that is such a bad drawing dw:1434347809810:dw a little circle geometry the perpendicular line from the centre to a chord, bisects the chord...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434348391396:dw so find y using pythagoras' theorem... because if OP bisects FG the PF = 16 and you know OP = 14 y will be a radius. then you can use that to draw another radius for the other side

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434348508637:dw so use pyhtagoras again to find x, knowing that OQ bisects SR hope it helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the answer 19.5? @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.219.5 is the length of QS

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434348916381:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x is 14 @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2no x is not 14... use pythagoras to find y \[y^2 = 16^2 + 14^2\] you can leave it as y^2 what do you get... ?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well lets just say \[y^2 = 452\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah ik thats what i got but but not squared its 20.8

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2then looking at finding x, and using pythagoras again you will have \[y^2 = x^2 + 19.5^2\] which can be rewritten as \[x^2 = y^2  19.5^2\] making the substitution \[x^2 = 452  19.5^2\] and from here you should be able to find x
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