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anonymous

  • one year ago

fg is perpendicular to op, rs is perpendicular to oq, fg=32, rs=39 and op=14. find the value of x

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  1. anonymous
    • one year ago
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    |dw:1434347870486:dw|

  2. anonymous
    • one year ago
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    a). 19.5 b). 20.8 c). 14 d). 8.5

  3. campbell_st
    • one year ago
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    wow that is such a bad drawing |dw:1434347809810:dw| a little circle geometry the perpendicular line from the centre to a chord, bisects the chord...

  4. anonymous
    • one year ago
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    o?

  5. anonymous
    • one year ago
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    @campbell_st

  6. campbell_st
    • one year ago
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    |dw:1434348391396:dw| so find y using pythagoras' theorem... because if OP bisects FG the PF = 16 and you know OP = 14 y will be a radius. then you can use that to draw another radius for the other side

  7. campbell_st
    • one year ago
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    |dw:1434348508637:dw| so use pyhtagoras again to find x, knowing that OQ bisects SR hope it helps

  8. campbell_st
    • one year ago
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    hope it helps

  9. anonymous
    • one year ago
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    is the answer 19.5? @campbell_st

  10. campbell_st
    • one year ago
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    19.5 is the length of QS

  11. campbell_st
    • one year ago
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    |dw:1434348916381:dw|

  12. anonymous
    • one year ago
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    x is 14 @campbell_st

  13. campbell_st
    • one year ago
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    no x is not 14... use pythagoras to find y \[y^2 = 16^2 + 14^2\] you can leave it as y^2 what do you get... ?

  14. anonymous
    • one year ago
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    20.8 @campbell_st

  15. campbell_st
    • one year ago
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    well lets just say \[y^2 = 452\]

  16. anonymous
    • one year ago
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    yeah ik thats what i got but but not squared its 20.8

  17. campbell_st
    • one year ago
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    then looking at finding x, and using pythagoras again you will have \[y^2 = x^2 + 19.5^2\] which can be re-written as \[x^2 = y^2 - 19.5^2\] making the substitution \[x^2 = 452 - 19.5^2\] and from here you should be able to find x

  18. anonymous
    • one year ago
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    8.5

  19. campbell_st
    • one year ago
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    thats what I got

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