ganeshie8
  • ganeshie8
Find the y intercepts of \[\large y=\frac{3x^3-x}{x^2-4x}\]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
campbell_st
  • campbell_st
so for the y, intercept, don't you let x = 0 but factor out x 1st \[y = \frac{x(3x^2 - 1)}{x(x - 4)}\]
ganeshie8
  • ganeshie8
Am i really allowed to let x = 0 here
kanwal32
  • kanwal32
3x^2-y(x-4)-1 and putting d>0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

campbell_st
  • campbell_st
well if you factor out x you get \[y=\frac{3x^2 -1}{x - 4}\] and to find the y-intercept for any curve... its a case of letting x = 0 so \[y = \frac{3\times0^2 - 1}{0 - 4}\]
ganeshie8
  • ganeshie8
don't we need to worry about the fact that x=0 is not part of the domain
campbell_st
  • campbell_st
x = 0 would be a point of discontinuity the way I read the question and work on the solution. lol... now I see your point...
ganeshie8
  • ganeshie8
Haha mother wolfram also says (0, 1/4) is the y intercept http://www.wolframalpha.com/input/?i=y+intercepts+%283x%5E3-x%29%2F%28x%5E2-4x%29
campbell_st
  • campbell_st
here is my graph of the equation
1 Attachment
ganeshie8
  • ganeshie8
It is a point discontinuity, should not be part of the domain
campbell_st
  • campbell_st
so then the curve doesn't have a y-intercept as its discontinuous at that point
campbell_st
  • campbell_st
I'm only in high school... so they may do other things at university
ganeshie8
  • ganeshie8
Exactly! there should not be any y intercepts for this curve but idk what wolfram is thinking lol
ganeshie8
  • ganeshie8
Your graphing calculator is correctly saying (0, 1/4) is a point discont
campbell_st
  • campbell_st
I'm in Australia and some people, I think from the US seem to not consider a point discontinuity anyway... glad you have a solution
Anikate
  • Anikate
lol this is confusing, I'll just have my teacher explain it to me tomorrow
anonymous
  • anonymous
Yet at the same time wolfram tells us the obvious domain http://www.wolframalpha.com/input/?i=domain+%283x^3-x%29%2F%28x^2-4x%29 Wolfram contradicts itself?
anonymous
  • anonymous
I think after simplifying we can not let \(x=0\) and the graph of the function must be|dw:1434357482874:dw|
ganeshie8
  • ganeshie8
then im convinced wolfram is lying about the y intercept
jigglypuff314
  • jigglypuff314
or perhaps some definition of a y intercept somewhere includes the limit?

Looking for something else?

Not the answer you are looking for? Search for more explanations.