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ganeshie8
 one year ago
Find the y intercepts of \[\large y=\frac{3x^3x}{x^24x}\]
ganeshie8
 one year ago
Find the y intercepts of \[\large y=\frac{3x^3x}{x^24x}\]

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so for the y, intercept, don't you let x = 0 but factor out x 1st \[y = \frac{x(3x^2  1)}{x(x  4)}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Am i really allowed to let x = 0 here

kanwal32
 one year ago
Best ResponseYou've already chosen the best response.13x^2y(x4)1 and putting d>0

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well if you factor out x you get \[y=\frac{3x^2 1}{x  4}\] and to find the yintercept for any curve... its a case of letting x = 0 so \[y = \frac{3\times0^2  1}{0  4}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3don't we need to worry about the fact that x=0 is not part of the domain

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1x = 0 would be a point of discontinuity the way I read the question and work on the solution. lol... now I see your point...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Haha mother wolfram also says (0, 1/4) is the y intercept http://www.wolframalpha.com/input/?i=y+intercepts+%283x%5E3x%29%2F%28x%5E24x%29

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1here is my graph of the equation

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3It is a point discontinuity, should not be part of the domain

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so then the curve doesn't have a yintercept as its discontinuous at that point

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1I'm only in high school... so they may do other things at university

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Exactly! there should not be any y intercepts for this curve but idk what wolfram is thinking lol

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Your graphing calculator is correctly saying (0, 1/4) is a point discont

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1I'm in Australia and some people, I think from the US seem to not consider a point discontinuity anyway... glad you have a solution

Anikate
 one year ago
Best ResponseYou've already chosen the best response.1lol this is confusing, I'll just have my teacher explain it to me tomorrow

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yet at the same time wolfram tells us the obvious domain http://www.wolframalpha.com/input/?i=domain+%283x^3x%29%2F%28x^24x%29 Wolfram contradicts itself?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think after simplifying we can not let \(x=0\) and the graph of the function must bedw:1434357482874:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3then im convinced wolfram is lying about the y intercept

jigglypuff314
 one year ago
Best ResponseYou've already chosen the best response.0or perhaps some definition of a y intercept somewhere includes the limit?
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