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Anikate
 one year ago
how do u do this?
cos2θ+cosθ=0
find solutions
Anikate
 one year ago
how do u do this? cos2θ+cosθ=0 find solutions

This Question is Closed

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1As a start, factor out \(\large \cos\theta\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Ahh that is wrong, and don't wry thats a typical mistake committed by everyone in the start

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \cos^2\theta\) is same as \(\large (\cos \theta)^2\)

Anikate
 one year ago
Best ResponseYou've already chosen the best response.1lol idk how that helps

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1when you factor out \(\cos\theta\) from \((\cos\theta)^2\), there will be \(\cos\theta\) left behind : dw:1434352204156:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1next use zero product property if the product of two factors is 0, then at least one of the factors must be 0

Anikate
 one year ago
Best ResponseYou've already chosen the best response.1ok so the cos theta on the outside is = to 0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434352435421:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1we need to find \(\theta\) using unit circle

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1for what values of \(\theta\), the cos function becomes 0 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1careful, do u have unit circle ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1The first coordinate represents the cosine value : dw:1434352712518:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1No, listen to my question again. For what values of \(\theta\), the cosine function is 0 ?

Anikate
 one year ago
Best ResponseYou've already chosen the best response.1hey is 3:20am here, I can barely concentrate, can u please leave the work, and I'll check back in the morning? sorry and thanks for all ur help and co operation! :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Assuming we want to find the principle value, from the unit circle, \[\cos\theta = 0 \implies \theta = 90,270\] \[\cos\theta = 1 \implies \theta = 180\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so \(\theta = 90,180,270\) are the solutions
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