anonymous
  • anonymous
Solve the system of equations given as x^2 +y^2 =16 y-4 = -x^2
Mathematics
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anonymous
  • anonymous
Solve the system of equations given as x^2 +y^2 =16 y-4 = -x^2
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
We have x^2=4-y , from the second equation.So we replace it to the first one : 4-y+y^2=16 @Romwil
campbell_st
  • campbell_st
well you have a circle with a centre at the origin and readius 4 and a concave down parabola with a vertex at (0, 4)
campbell_st
  • campbell_st
so there are 3 points of intersection...

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anonymous
  • anonymous
Refer to the attachment generated with the Mathematica 9 program.
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Sepeario
  • Sepeario
props to him ^^ he has taken the time to graphically solve it with a calculator, rather than completely algebraically :)

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