## anonymous one year ago plz help! show steps. fan and medal! Part A: if (6^2)^x=1 , what is the value of x? Part B: If (6^0)^x=1, what are the possible values of x?

1. Nnesha

$\huge \rm(2x)^0$ anything to the zero power is just = 1 $\rm (Nnesha)^0 =1$

2. anonymous

wait but how does that apply to the problem? then would part a be (6^2)^x=1 x would be 1? or 0?

3. Nnesha

let's try $(6^2)^1 = ??$ apply this exponent rule $\huge\rm (X^m)^n = x^{ m \times n}$ $(6^2)^0 = ???$

4. anonymous

0?

5. Nnesha

for which one ?? $(6^2)^1 = ??$ $(6^2)^0 = ???$

6. anonymous

part a= 2 part b= 0 am I right? is it that simple?

7. Nnesha

nope what i said about 0 exponent ?? read my first comment

8. anonymous

idk. im so lost. im doing a timed assignment. and I am so lost. can you show me the steps like work out the problem. so that I can understand what you are saying more clearly.

9. Nnesha

anything to the 0 power is always going to be equal to one EXAMPLES $(3x)^0 =1$$(34522)^0=1$

10. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @magy33 wait but how does that apply to the problem? then would part a be (6^2)^x=1 x would be 1? or 0? $$\color{blue}{\text{End of Quote}}$$ let x =1 $(6^2)^1= 1$is it right both sides are equal ??

11. Nnesha

(6^2)^1 =what ?

12. anonymous

1? so x is 1 in both equations?

13. Nnesha

14. Nnesha

tell me (6^2)^1 =what ??

15. anonymous

6^2?

16. Nnesha

yes 6^2 =36 and $36\cancel{ = }1$ so x is not 1

17. Nnesha

now what about $\huge\rm (6^2)^0=??$

18. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha $\huge \rm(2x)^0$ anything to the zero power is just = 1 $\rm (Nnesha)^0 =1$ $$\color{blue}{\text{End of Quote}}$$

19. anonymous

6^0? but then what are the possible values of x? o.o

20. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha now what about $\huge\rm (6^2)^0=??$ $$\color{blue}{\text{End of Quote}}$$ here i substituted 0 for x so (6^2)^0= what ?

21. anonymous

6^0?

22. Nnesha

no

23. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha $\huge \rm(2x)^0$ anything to the zero power is just = 1 $\rm (Nnesha)^0 =1$ $$\color{blue}{\text{End of Quote}}$$ read this

24. anonymous

6^2= 1? huh. im lost what are the possible values of x. 0.0

25. Nnesha

well not just 6^2 (6^2)^0 equal what

26. Nnesha

6^2 is equal to 36

27. anonymous

wait this is for part b?

28. Nnesha

i said ANYTHING ANYTHING to the zero power is = 1 $\rm (832htx)^0=1$

29. Nnesha

nope part A

30. anonymous

ok I got that but the question I am asking is for part b. PArt B is this: if (6^0)^x=1 , what are the possible values of x? I got part a already.

31. Nnesha

so u got for part a ??? and part b is same First of all solve the parentheses $(6^0 )^x = (???)^x$ 6^0 = what ?

32. anonymous

0.

33. Nnesha

you tell me is that right 6 to the ZERO power equal =0 ??

34. anonymous

yes because nothing multiplied by 0 is anything else but 0. 6^0=0. so what are the values. I got 5 minutes to turn this in.

35. Nnesha

is it a test question ??

36. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @magy33 yes because nothing multiplied by 0 is anything else but 0. 6^0=0. so what are the values. I got 5 minutes to turn this in. $$\color{blue}{\text{End of Quote}}$$ i told you anything to the zero power is equaal to one

37. Nnesha

3^0 =1 6^0 = what ??

38. Nnesha

therre are 2 possible values for part B

39. anonymous

so the the naswers are 1? that's my possible x values? for part B? 1? and 1?

40. Nnesha

6^0 = what ??

41. Nnesha

nope one of them is one for part B 2nd one is what ?

42. Nnesha

6^0 = what ??

43. anonymous

1 and 0?

44. Nnesha

yes right $(6^0)^0 = (1)^0 = 1 ~~~~(6^0)^1=(1)^1 =1$