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Part A: if (6^2)^x=1 , what is the value of x?
Part B: If (6^0)^x=1, what are the possible values of x?

- anonymous

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- Nnesha

\[\huge \rm(2x)^0\] anything to the zero power is just = 1
\[\rm (Nnesha)^0 =1\]

- anonymous

wait but how does that apply to the problem?
then would part a be (6^2)^x=1 x would be 1? or 0?

- Nnesha

let's try \[(6^2)^1 = ??\] apply this exponent rule \[\huge\rm (X^m)^n = x^{ m \times n}\]
\[(6^2)^0 = ???\]

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## More answers

- anonymous

0?

- Nnesha

for which one ??
\[(6^2)^1 = ??\] \[(6^2)^0 = ???\]

- anonymous

part a= 2
part b= 0
am I right? is it that simple?

- Nnesha

nope what i said about 0 exponent ?? read my first comment

- anonymous

idk. im so lost. im doing a timed assignment. and I am so lost. can you show me the steps like work out the problem. so that I can understand what you are saying more clearly.

- Nnesha

anything to the 0 power is always going to be equal to one
EXAMPLES \[(3x)^0 =1\]\[(34522)^0=1\]

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @magy33
wait but how does that apply to the problem?
then would part a be (6^2)^x=1 x would be 1? or 0?
\(\color{blue}{\text{End of Quote}}\)
let x =1 \[(6^2)^1= 1\]is it right both sides are equal ??

- Nnesha

(6^2)^1 =what ?

- anonymous

1? so x is 1 in both equations?

- Nnesha

no i'm asking a question

- Nnesha

tell me (6^2)^1 =what ??

- anonymous

6^2?

- Nnesha

yes 6^2 =36
and
\[36\cancel{ = }1\] so x is not 1

- Nnesha

now what about \[\huge\rm (6^2)^0=??\]

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge \rm(2x)^0\] anything to the zero power is just = 1
\[\rm (Nnesha)^0 =1\]
\(\color{blue}{\text{End of Quote}}\)

- anonymous

6^0? but then what are the possible values of x? o.o

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
now what about \[\huge\rm (6^2)^0=??\]
\(\color{blue}{\text{End of Quote}}\)
here i substituted 0 for x
so (6^2)^0= what ?

- anonymous

6^0?

- Nnesha

no

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge \rm(2x)^0\] anything to the zero power is just = 1
\[\rm (Nnesha)^0 =1\]
\(\color{blue}{\text{End of Quote}}\)
read this

- anonymous

6^2= 1? huh. im lost what are the possible values of x. 0.0

- Nnesha

well not just 6^2
(6^2)^0 equal what

- Nnesha

6^2 is equal to 36

- anonymous

wait this is for part b?

- Nnesha

i said ANYTHING ANYTHING to the zero power is = 1 \[\rm (832htx)^0=1\]

- Nnesha

nope part A

- anonymous

ok I got that but the question I am asking is for part b. PArt B is this:
if (6^0)^x=1 , what are the possible values of x? I got part a already.

- Nnesha

so u got for part a ???
and part b is same
First of all solve the parentheses \[(6^0 )^x = (???)^x\]
6^0 = what ?

- anonymous

0.

- Nnesha

you tell me is that right
6 to the ZERO power equal =0 ??

- anonymous

yes because nothing multiplied by 0 is anything else but 0. 6^0=0. so what are the values. I got 5 minutes to turn this in.

- Nnesha

is it a test question ??

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @magy33
yes because nothing multiplied by 0 is anything else but 0. 6^0=0. so what are the values. I got 5 minutes to turn this in.
\(\color{blue}{\text{End of Quote}}\)
i told you anything to the zero power is equaal to one

- Nnesha

3^0 =1
6^0 = what ??

- Nnesha

therre are 2 possible values for part B

- anonymous

so the the naswers are 1? that's my possible x values?
for part B? 1? and 1?

- Nnesha

6^0 = what ??

- Nnesha

nope one of them is one for part B
2nd one is what ?

- Nnesha

6^0 = what ??

- anonymous

1 and 0?

- Nnesha

yes right \[(6^0)^0 = (1)^0 = 1 ~~~~(6^0)^1=(1)^1 =1\]

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