plz help! show steps. fan and medal!
Part A: if (6^2)^x=1 , what is the value of x?
Part B: If (6^0)^x=1, what are the possible values of x?

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\[\huge \rm(2x)^0\] anything to the zero power is just = 1
\[\rm (Nnesha)^0 =1\]

wait but how does that apply to the problem?
then would part a be (6^2)^x=1 x would be 1? or 0?

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